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3 years ago

Describe how the land and ocean nitrogen cycles are similar

1 answer:

4 0

Land and ocean nitrogen cycles follow the same cycle. From nitrogen fixation, Assimilation, Ammonification, Nitrification, and Denitrification. What differs are only the players processing in each cycle and the mode of transfer from one cycle to another. For example in nitrogen fixation, nitrogen on land came from the atmosphere while in the ocean it came dissolved nitrogen through precipitation or runoff. Players in fixation are bacteria such as rhizobium and its counterpart in the ocean are the cyanobacteria.

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The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi

avanturin [10]

Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

$Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)$

The balanced two-half reactions will be,

Oxidation half reaction : $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction : $Ni^{2+}+2e^-\rightarrow Ni$

The expression for reaction quotient will be :

$Q=\frac{[Zn^{2+}]}{[Ni^{2+}]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(0.0141)}{(0.00104)}=13.6$

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

$E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

$E^o_{cell}$ = standard electrode potential of the cell = 0.51 V

$E_{cell}$ = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

$E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)$

$E_{cell}=0.47V$

Therefore, the actual cell potential of the cell is 0.47 V

4 0

4 years ago

What is the ionization charge for the elements found in Group II?

ser-zykov [4K]

Answer: a + 2

Explanation: Alkali Earths or Group II has an ionization charge of a + 2. Alkali Metals have a ionization a + 1. Halogens or cold elements have a ionization of a +3.

5 0

3 years ago

What apparatus is used to measure small volume of liquid

Doss [256]

Answer:

give me brainliest pls

Explanation:

Volumetric flasks

Volumetric labware is for measuring liquids with precision. Volumetric flasks, burettes, and pipettes made for measuring small amounts of liquid are the most accurate, with tolerances of less than ±0.02.

7 0

3 years ago

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For the imine synthesis reaction, the two reactants react in melting state. How is that possible since the melting points for bo

pychu [463]

Answer:

I have no clue at all im in 11 and dont know anything lol byeeee

Explanation:um um i am lost

7 0

3 years ago

How does math relate to electrons and ion formation?

Elenna [48]

In order to find the NET nuclear charge from an atom's valence electron to the proton nucleus, you need to do some simple math in order to find the charge.

You would also need to apply math when you need to figure out what the charge on an ion is by either adding or taking away electrons depending on whether it is an anion or cation.

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3 years ago

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