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2 years ago

15

Which process is spontaneous? electrolysis of water into oxygen and hydrogen spreading of a strong fragrance of perfume in a roo

m separation of sodium and chlorine from sodium chloride removal of iron fillings from a mixture by using a magnet?

1 answer:

dmitriy555 [2]2 years ago

3 0

Yes I think oxides I's the answer

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Draw the structure of the product of each step in the following three-step synthesis. Show the formal charges, if applicable. As

Dvinal [7]

Answer:

Second step: 4-bromo-1-methyl-2-nitrobenzene.

Third step: 1.5-dibromo-2-methyl-3-nitrobenzene.

Explanation:

To solve this exercise I will use the concepts of electrophilic substitution. In these reactions, a functional group is displaced by an electrophile. In the attached image are the two main products.

5 0

3 years ago

Draw the structure(s) of the major organic product(s) of the following reaction. 1. lithium diisopropylamide / hexane 2. 1 eq. C

Jobisdone [24]

Answer:

See explanation below

Explanation:

You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.

Now let's analyze what is happening in the reaction so we can predict the final product.

We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.

Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.

Hope this helps

6 0

2 years ago

How did Thomson show that cathode<br> rays are different from light?

Flura [38]

Answer:

They had a negative charge

Explanation:

5 0

2 years ago

Nitric acid, , is manufactured by the Ostwald process, in which nitrogen dioxide, , reacts with water. How many grams of nitroge

aleksandr82 [10.1K]

Answer:

7.04 g

Explanation:

Let's consider the reaction in the last step of the Ostwald process.

3 NO₂(g) + H₂O(l) → 2 HNO₃(aq) + NO(g)

The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 6.40 g are:

6.40 g × (1 mol/63.01 g) = 0.102 mol

The molar ratio of NO₂ to HNO₃ is 3:2. The reacting moles of NO₂ are:

0.102 mol HNO₃ × (3 mol NO₂/2 mol HNO₃) = 0.153 mol NO₂

The molar mass of NO₂ is 46.01 g/mol. The mass corresponding to 0.153 moles is:

0.153 mol × (46.01 g/mol) = 7.04 g

5 0

3 years ago

A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the

butalik [34]

Answer:

0.172 M

Explanation:

The reaction for the first titration is:

HCl + NaOH → NaCl + H₂O

First we <u>calculate how many HCl moles reacted</u>, using the <em>given concentration and volume</em>:

19.6 mL * 0.189 M = 3.704 mmol HCl

As one HCl mol reacts with one NaOH mol, <em>there are 3.704 NaOH mmoles in 25.0 mL of solution</em>. With that in mind we <u>determine the NaOH solution concentration</u>:

3.704 mmol / 25.0 mL = 0.148 M

As for the second titration:

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

We <u>determine how many NaOH moles reacted</u>:

34.9 mL * 0.148 M = 5.165 mmol NaOH

Then we <u>convert NaOH moles into H₃PO₄ moles</u>, using the <em>stoichiometric coefficients</em>:

5.165 mmol NaOH * $\frac{1mmolH_3PO_4}{3mmolNaOH}$ = 1.722 mmol H₃PO₄

Finally we <u>determine the H₃PO₄ solution concentration</u>:

1.722 mmol / 10.0 mL = 0.172 M

5 0

2 years ago