Answer: You spent 5 hours babysitting.
Step-by-step explanation:
This situation can be represented by the equation y = 8x+ 10 where y is the money you earn and x is the number of hours.
So if y is equation to fifty dollars then what is x ?
50 = 8x +10 subtract 10 from both sides.
-10 -10
40 = 8x
x = 5
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




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a. The marginal densities

and

b. This can be obtained by integrating the joint density over [0.25, 1] x [0.5, 1]:

Answer:
Part 1) The exact value of the arc length is 
Part 2) The approximate value of the arc length is 
Step-by-step explanation:
step 1
Find the circumference of the circle
The circumference of a circle is equal to

we have

substitute


step 2
Find the exact value of the arc length by a central angle of 150 degrees
Remember that the circumference of a circle subtends a central angle of 360 degrees
by proportion

step 3
Find the approximate value of the arc length
To find the approximate value, assume

substitute

I think that
the triangle is 6
the square is -5
and the star is -20
but i would get a second answer bc i cant certainly say that<span />