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3 years ago

With the crate stationary on a horizontal ramp, the force of static friction is:_________

Physics

1 answer:

padilas [110]3 years ago

6 0

Answer:

Zero

Explanation:

As it is stationary, it implies a non moving force, on top of the fact that the ramp is horizontal, the force of static friction has to be zero.

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How much Gravitational Potential Energy does a 1.48 kg book at rest on top of a 2.4 m tall desk have?

Naily [24]

Gravitational Potential Energy GPE = mg∆h. 12. A 5.0 kg mass is initially sitting on the floor when it is lifted onto a table 1.15 meters high at.

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2 years ago

4. A disobedient student dropped his Physics textbook (mass 0.1kg) from the window (15m above the ground). How fast was it going

vaieri [72.5K]

Answer:

v= 17.15 m/s

Explanation:

mass of the book=0.1 Kg

height above ground, h= 15 m

Using conservation of energy

Potential energy is converted into kinetic energy

$mgh = \frac{1}{2}mv^2$

$v=\sqrt{2gh}$

$v=\sqrt{2\times 9.8\times 15}$

$v=\sqrt{294}$

v= 17.15 m/s

Hence, the book will hit the ground at the speed of 17.15 m/s.

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2 years ago

In 1970, a rocket powered car called Blue Flame achieved a maximum speed of 1.00(10 km/h (278m/s).Suppose the magnitude of the c

sammy [17]

Answer:

Distance traveled during this acceleration will be 6950 m

Explanation:

Wear have given maximum speed tat will be equal to final speed of the car v = 278 m/sec

Constant acceleration $a=5.56m/sec^2$

As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec

From third equation of motion $v^2=u^2+2as$

Putting all values in equation

$278^2=0^2+2\times 5.56\times s$

s = 6950 m

So distance traveled during this acceleration will be 6950 m

3 0

3 years ago

A system gains 767 kJ of heat, resulting in a change in internal energy of the system equal to +151 kJ. How much work is done?

Crazy boy [7]

Answer:

The work done on the system is -616 kJ

Explanation:

Given;

Quantity of heat absorbed by the system, Q = 767 kJ

change in the internal energy of the system, ΔU = +151 kJ

Apply the first law of thermodynamics;

ΔU = W + Q

Where;

ΔU is the change in internal energy

W is the work done

Q is the heat gained

W = ΔU - Q

W = 151 - 767

W = -616 kJ (The negative sign indicates that the work is done on the system)

Therefore, the work done on the system is -616 kJ

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3 years ago

Does the tide that the moon raises on the earth different?

alukav5142 [94]

Answer:

No the gravity of the moon pulls the water making high tide

Explanation:

7 0

3 years ago