**Explanation:**

Using Coulomb's law, the relation between force and charge is as follows.

F =

In the given case, = q

Hence,

F =

Squaring on both the sides, we get

q =

=

= C

=

Thus, we can conclude that **magnitude of the charge on each grape is .**

<h3>

**<u>Correction</u>****<u>:</u>****<u>-</u>**</h3>

Prove that v² = u² + 2as .

<h3>

**<u>Solution</u>****<u>:</u>****<u>-</u>**</h3>

From first equation of motion,

v = u + at

=> at = v - u

=> t = v - u / a

From the second equation of motion, we have

s = ut + 1/2at²

Putting the value of t in above equation , we get:

s = u ( v - u /a ) + 1/2 a ( v - u/a )²

s = uv - u² / a + a( v² + u² - 2uv / 2a²)

s = uv - u² / a + v² + u² - 2uv / 2a

s = 2uv - 2u² + v² + u² - 2uv / 2a

2as = v² - u²

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If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).

Answer: 0.076 m/s

Explanation:

Momentum is conserved:

m v = (m + M) V

(0.111 kg) (55 m/s) = (0.111 kg + 80. kg) V

V = 0.076 m/s

After catching the puck, the goalie slides at 0.076 m/s.

**Answer:**

2 m/s

**Explanation:**

= Mass of red truck = 1000 kg

= Mass of green truck= 3000 kg

= Initial Velocity of red truck = 6 m/s

= Initial Velocity of green truck

= Velocity with which they move together = 0

For elastic collision

**Velocity of the green truck is 2 m/s**