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Lostsunrise [7]
2 years ago
7

Akito pushes a wheelbarrow with 800 W of power. How much work is required to get the wheelbarrow across the yard in 12 s? Round

your answer to the nearest whole number.
It takes blank J of work to get the wheelbarrow across the yard
Physics
2 answers:
masha68 [24]2 years ago
5 0

Answer:

9600 J

Explanation:

The power is given by the ratio between the work done and the time taken:

P=\frac{W}{t}

where W is the work done and t the time taken.

In this problem, we know the power:

P = 800 W

and the time taken:

t = 12 s

So, we can re-arrange the equation to get the work required:

W=Pt=(800 W)(12 s)=9600 J

12345 [234]2 years ago
4 0
800 x 12 = 9,600
9,600 is your answer
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you decide to work part time at a local supermarket. The job pays eight dollars and 60 per hour and you work 20 hours per week.
aleksley [76]

Answer:

I guess that we want to find how much money you get each week.

We know that the job pays $8.60 per hour.

We know that you work 20 hours per week.

Then the gross pay (the total money that you earn) in a week is 20 times $8.60, or:

20*$8.60 = $172.

Now we know that your employer witholds:

10% + 7.65% + 5% = 22.65%

Then your employer withholds 22.65% of your gross pay.

if the 100% of your gross pay is $172

Then the 22.65% will be:

(22.65%/100%)*$172 = 0.2265*$172 = $38.96

This means that your employer withholds $38.96 of your weekly gross pay.

Then each week you get:

$172 - $38.96 = $133.04

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2 years ago
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Answer:

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6 0
3 years ago
What is motivation in your own world
hjlf

Answer:

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5 0
2 years ago
Three capacitors having capacitances of 8.40, 8.40, and 4.20 μFμF, respectively, are connected in series across a 36.0-V potenti
son4ous [18]

Answer:

a)Q=71.4 μ C

b)ΔV' = 10.2 V

Explanation:

Given that

C ₁= 8.7 μF

C₂ = 8.2 μF

C₃ = 4.1 μF

The potential difference of the battery, ΔV= 34 V

When connected in series

1/C = 1/C ₁ + 1/C₂ + 1/C₃

1/ C= 1/8.4 +1 / 8.4 + 1/4.2

C=2.1 μF

As we know that when capacitor are connected in series then they have same charge,Q

Q= C ΔV

Q= 2.1 x 34 μ C

Q=71.4 μ C

b)

As we know that when capacitor are connected in parallel then they have same voltage difference.

Q'= C' ΔV'

C'= C ₁+C₂+C₃        (For parallel connection)

C'= 8.4 + 8.4 + 4.2 μF

C'=21 μF

Q'= C' ΔV'

Q'=3 Q

3 x 71.4= 21 ΔV'

ΔV' = 10.2 V

3 0
3 years ago
In models of magnetic and electric fields, why are field vectors depicted by arrows?
taurus [48]

The arrows in models of magnetic and electric fields show  both their magnitude and direction.

In Physics, a vector refers to a quantity that has both magnitude and direction. Hence, a vector always points in a given direction. The direction in which the arrow points is the direction of the vector in space.

In models of magnetic and electric fields, field vectors depicted by arrows  because they represent both their magnitude and direction. The length of the arrow shows magnitude.

Learn more: brainly.com/question/102477

7 0
2 years ago
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