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Lostsunrise [7]
3 years ago
7

Akito pushes a wheelbarrow with 800 W of power. How much work is required to get the wheelbarrow across the yard in 12 s? Round

your answer to the nearest whole number.
It takes blank J of work to get the wheelbarrow across the yard
Physics
2 answers:
masha68 [24]3 years ago
5 0

Answer:

9600 J

Explanation:

The power is given by the ratio between the work done and the time taken:

P=\frac{W}{t}

where W is the work done and t the time taken.

In this problem, we know the power:

P = 800 W

and the time taken:

t = 12 s

So, we can re-arrange the equation to get the work required:

W=Pt=(800 W)(12 s)=9600 J

12345 [234]3 years ago
4 0
800 x 12 = 9,600
9,600 is your answer
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The generator at a power plant produces AC at 20,000 V. A transformer steps this up to 355,000 V for transmission over power lin
Masja [62]

Answer:

Number of coil in the output is 39938

Explanation:

We have given a step up transformer

Input voltage of transformer, that is primary voltage v_p=20000volt

Output voltage, that is secondary voltage v_s=355000volt

Number of turns in primary N_p=2250

For transformer we know that \frac{V_p}{V_s}=\frac{N_p}{N_s}

\frac{20000}{355000}=\frac{2250}{N_s}

N_s=39937.5

As the number of turns can not be in fraction so number of turns in the output coil is 39938

7 0
3 years ago
How can inclined planes change the amount of force to move an object? A. Increase height of the inclined plane B. Increase dista
mash [69]

Answer:

Option ( B ) is correct .

Explanation:

To lift a heavy weight , inclined plane is used . Use of inclined plane , makes the task easier because instead of force mg , force mg sinθ is to be used which is less than mg . Here θ is inclination of inclined plane.

If h be the height by which weight is to be lifted

potential energy acquired by weight = mgh

work done by force mg sinθ = mgsinθ x d where d is displacement required .

mg sinθ x d = mgh  ( work done by force = potential energy stored in luggage )

d = h / sinθ

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Hence inclined plane increases the distance to be covered by force applied though it decreases the force itself.

Hence option ( B ) is correct .

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3 years ago
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