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2 years ago

15

If a car moving down this road rounds this curve and changes its direction to the right, is this an example of speed, velocity,

or acceleration?

2 answers:

Strike441 [17]2 years ago

8 0

Answer:

That would be velocity since its a change in derection

Explanation:

mars1129 [50]2 years ago

4 0

Answer: velocity

Explanation: it's the rate of change of the objects position/ consistent change

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How is speed determined?

enot [183]

Speed equals distance divided by time (Speed=Distance/Time).

For example if it takes someone three minutes to go three miles their speed is one mile a minute.

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3 years ago

What does the number, or density, of field lines on a source charge indicate?

Harrizon [31]

Hello.

The answer: C. amount of charge on the source charge

The field lines all represent the movements of field charges. The more crowded the field lines or the more density of electric field the higher is the magnitude of the source charge.

Have a nice day.

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3 years ago

Read 2 more answers

A 0.250 kgkg toy is undergoing SHM on the end of a horizontal spring with force constant 300 N/mN/m. When the toy is 0.0120 mm f

konstantin123 [22]

Answer:

(a) The total energy of the object at any point in its motion is 0.0416 J

(b) The amplitude of the motion is 0.0167 m

(c) The maximum speed attained by the object during its motion is 0.577 m/s

Explanation:

Given;

mass of the toy, m = 0.25 kg

force constant of the spring, k = 300 N/m

displacement of the toy, x = 0.012 m

speed of the toy, v = 0.4 m/s

(a) The total energy of the object at any point in its motion

E = ¹/₂mv² + ¹/₂kx²

E = ¹/₂ (0.25)(0.4)² + ¹/₂ (300)(0.012)²

E = 0.0416 J

(b) the amplitude of the motion

E = ¹/₂KA²

$A = \sqrt{\frac{2E}{K} } \\\\A = \sqrt{\frac{2*0.0416}{300} } \\\\A = 0.0167 \ m$

(c) the maximum speed attained by the object during its motion

$E = \frac{1}{2} mv_{max}^2\\\\v_{max} = \sqrt{\frac{2E}{m} } \\\\v_{max} = \sqrt{\frac{2*0.0416}{0.25} } \\\\v_{max} = 0.577 \ m/s$

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3 years ago

A train moving at 5 m/sec passed a track gang and then accelerated uniformly a rate of 1.2 m/sec/sec for 5 min. How far did the

Amanda [17]

Answer:

S = V0 t + 1/2 a t^2

S = 5 m/s * 300 s + 1/2 * 1.2 m/s * (300 s^2)

S = 1500 m + .6 * 90000 m = 55,500 m

Check: V0 = 5 m/s

V2 = V0 + a t = 5 + 1.2 * 300 = 365 m/s

Vav = (V1 + V2) / 2 = (5 + 365) / 2 = 185 m/s (note uniform motion)

S = 185 * 300 = 55,500 m

We calculated V2 above at 365 m/s the speed after 300 sec

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2 years ago

What is the purpose of heat index

Nookie1986 [14]

<span>It tells how hot it really feels when the relative humidity is factored in with the actual air temperature.
hope this helps</span>

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3 years ago

Read 2 more answers