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3 years ago

A phonograph record 0.15 m in its radius rotates 18 times per 90 seconds what is the frequency?

Physics

1 answer:

ioda3 years ago

6 0

Answer:

The frequency of the phonograph record is 0.2 Hz

Explanation:

The frequency of an object moving in uniform circular motion is the number of completed cycles the object makes in a specified time period

The given parameters of the phonograph record are;

The radius of the record = 0.15 m

The number of times the phonograph record rotates, n = 18 times

The time it takes the phonograph record to rotate the 18 times, t = 90 seconds

The frequency of the phonograph record, f = (The number of times the phonograph record rotates) ÷ (The time it takes the phonograph record to rotate the 18 times)

∴ The frequency of the phonograph record, f = n/t = 18/(90 s) = 0.2 Hz

The frequency of the phonograph record = 0.2 Hz.

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Article 5 of the Fundamental Orders of Connecticut is MOST LIKELY related to which idea?

Sauron [17]

Answer:

Option A, Rule of law

Explanation:

The complete question is

Article 5 of the Fundamental Orders of Connecticut is MOST LIKELY related to which idea? A) rule of law B) personal freedom C) individual rights D) limited government

Solution

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3 years ago

A car accelerates at 3 m/s*2. Assuming the car starts from rest, how much time does it need to

uranmaximum [27]

<h3><u>Given</u><u>:</u><u>-</u></h3>

Acceleration,a = 3 m/s²

Initial velocity,u = 0 m/s

Final velocity,v = 12 m/s

<h3><u>To</u><u> </u><u>be</u><u> </u><u>calculated:-</u><u> </u></h3>

Calculate the time take by a car.

<h3><u>Solution:-</u><u> </u></h3>

According to the first equation of motion:

v = u + at

★ Substituting the values in the above formula,we get:

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⇒ 3t = 12

⇒ t = 12/3

⇒ t = 4 sec

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zavuch27 [327]

As it is given here

initial speed is

$v_i = 6 m/s$

After 4 seconds the final speed is

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As it is given here

initial it starts from rest

$v_i = 0 m/s$

After 2.5 seconds the final speed is

$v_f = 15 m/s$

so here we can use the formula of acceleration using kinematics

$a = \frac{v_f - v_i}{t}$

$a = \frac{15 - 0}{2.5}$

$a = 6 m/s^2$

so here it will accelerate at 6 m/s^2 rate.

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