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koban [17]
3 years ago
9

the mass of a small steel ball is 120g. the volume of the ball is 16.0 cm 3. calculate the density of th steel ball

Physics
1 answer:
Delicious77 [7]3 years ago
3 0

Answer:

7500

Explanation:

m=120g=0.12kg

v=16cm^3 = 0.000016m^3..

density=m/v

=(0.12/0.000016)kg/m^3

=7500kg/m^3

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If the potential difference across a 12-ohm resistor is 6 volts, the current through the resistor is?
larisa86 [58]
Current is inversely proportional to the resistance of the resistor and directly to the potential difference across it.

I = V/R = 6/12 = 0.5 A
4 0
3 years ago
An airplane maintains a speed of 585 km/h relative to the air it is flying through as it makes a trip to a city 815 km away to t
navik [9.2K]

Answer:

a)   t = 1.47 h    b) t = 1.32 h

Explanation:

a)  In this problem the plane and the wind are in the same North-South direction, whereby the vector sum is reduced to the scalar sum (ordinary). Let's calculate the total speed

     v = v_{f}f - v_{w}

     v = 585 -32.1

     v = 552.9 km / h

We use the speed ratio in uniform motion

     v = x / t

     t = x / v

     t = 815 /552.9

     t = 1.47 h

b)  We repeat the calculation, but this time the wind is going in the direction of the plane

      v=  v_{f}f - v_{w}

      v 585 + 32.1

      v = 617.1 km / h

      t = 815 /617.1

      t = 1.32 h

4 0
3 years ago
A skier of mass 82.9 kg starts from rest at the top of a frictionless incline of height 20 m. At the bottom of the incline, the
ehidna [41]

Answer: 170.67 N

Explanation:

Given

Mass of skier is m=82.9\ kg

Height of the inclination is h=20\ m

Here, the potential energy of the skier is converted into kinetic energy which is consumed by the friction force by applying a constant force that does work to stop the skier.

\Rightarrow mgh=F\cdot x\quad \quad [\text{F=constant friction force}]\\\\\Rightarrow 82.9\times 9.8\times 20=F\cdot 95.2\\\\\Rightarrow F=\dfrac{16,248.4}{95.2}\\\\\Rightarrow F=170.67\ N

Thus, the horizontal friction force is 170.67 N.

7 0
3 years ago
HELP ASAP!! i’ll mark you the brainliest!!
Triss [41]

Answer:

yes

Explanation:

6 0
2 years ago
A solid, uniform sphere with a mass of 2.5 kg rolls without slipping down an incline plane starting from rest at a vertical heig
kolezko [41]

Answer:

1/2 m v^2 + 1/2 I ω^2 = m g h       conservation of energy

I = 2/5 m R^2     inertia of solid sphere

1/2 m v^2 + 1/5 m ω^2 R^2 = m g h

1/2 v^2 + 1/5 v^2 = g h

v^2 = 10 g h / 7 = 1.43 * 9.80 * 19 m^2/s^2 = 266 m^2/s^2

v = 16.3 m/s

v = R ω

ω = 16.3 / .6 = 27.2 / sec

8 0
2 years ago
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