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3 years ago

Find the length of the midsegment.

Mathematics

1 answer:

STALIN [3.7K]3 years ago

7 0

Answer:

Step-by-step explanation:

The length of the midsegment is half the length of the base segment, so you have ...

... 2(6x +2) = 2x +84

... 10x = 80 . . . . . . . . . simplify, subtract 2x+4

... x = 8

The length of the midsegment is 6·8+2 = 50.

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3 years ago

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2 years ago

Read 2 more answers

a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F

slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

M= (c^2)/8 which is intern equal to 2 $\sqrt{2}$

Step-by-step explanation:

Find the area, by setting the limits as

= $4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}4d\theta$

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Therefore;

Mxy= $\int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta$

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means $4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta$

$4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)$

c=2 $\sqrt{2}$

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3 years ago