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Whitepunk [10]
4 years ago
9

Simplify square root of 5 { 6-4 square root of 3

Mathematics
1 answer:
Alex73 [517]4 years ago
5 0

Answer:

\sqrt{5 \: (6 - 4 \sqrt{3)} }

You mean that way?

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A contractor has at most $42 to spend on nails for a project. Finishing nails cost $0.45 per pound and
lara [203]

Answer:

Step-by-step explanation:

f(x)=42-0.45(x)  Solution 13.5 dollars expend in 30 Finishing nails

f(x)=42-0.60(x) Solution 18 dollars expend in 30 Common nails

4 0
3 years ago
Last year, Scout Troop # 85 sold 540 boxes of cookies. This year, they sold 783 boxes. What was the percent increase in the numb
lesantik [10]
Difference/original
783 - 540 = 243
243/540 = 0.45
0.45 * 100 = 45
45% = increased percentage
4 0
3 years ago
0.27 repeating in simplest form
NeTakaya
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The standard notation for a repeating decimal is to put a bar over the repeating digits, that is, <span>0.27272727...=0.27 repeating


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7 0
3 years ago
Read 2 more answers
An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.
MArishka [77]

Answer:

(a) 0.999664

(b) 15052

Step-by-step explanation:

From the given data of recent years,  there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is \frac{21}{3000000}==0.000007.

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by q.

q=7\times 10^{-6}=0.000007.

So, the probability of survive, p=1-q

\Rightarrow p=1-7\times 10^{-6}=0.999993.

(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

=\binom(n,r)p^rq^{n-r}

=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}

=(0.999993)^{48}=0.999664 (approx)

So, the probability of survive in 48 skydiving is 0.999664,

(b) The given probability of surviving =90%=0.9

Let, total n skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

0.9=\binom {n }{r} p^rq^{n-r}

Here, r=n.

\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}

\Rightarrow 0.9=p^n

\Rightarrow 0.9=(0.999993)^n

\Rightarrow \ln(0.9)=n\ln(0.999993) [ taking \log_e both sides]

\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}

\Rightarrow n=15051.45

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

3 0
3 years ago
PLEASE help it’s due today at 10pm
Bogdan [553]
Sorry bro its past 10pm now, hope you figured it out
7 0
3 years ago
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