<span>802 mm Hg X 13.5/1 = 10827 mm H2O X (1 cm/10 mm) = 1083 cm H2O = 1.08 X 10^3 cm H2O</span>
Answer:
The answer to your question is Mercury
Explanation:
The flame test essay is used to identify the identity of a substance because most elements show different colors when in flame.
There are many elements that burn violet when in flame especially elements of the group IA like Potassium, Rubidium, Cesium and also Cyanide and Mercury located in different groups.
But the bibliography tells us that Mercury chloride burns violet so this element is the correct answer because there is chloride in the sample of this question.
Answer:
The answer to your question is:
Explanation:
Data
carbon 7.3% = 7.3g
hydrogen 4.5% = 4.5g
oxygen 36.4% = 36.4 g
nitrogen 31.8% = 31.8 g
Now
For carbon
12 g --------------------1 mol
7.3 g ------------- x
x = 7.3/12 = 0.608 mol
For hydrogen
1 g -------------------- 1 mol
4.5 g ------------------ x
x = 4.5 mol
For oxygen
16 g ------------------- 1 mol
36.4 g ---------------- x
x = 2.28 mol
For nitrogen
14 g ---------------- 1 mol
31.8 g --------------- x
x = 2.27 mol
Now divide by the lowest result, the is 0.608 from carbon
carbon 0.608/0.608 = 1
hydrogen 4.5/ 0.608 = 7.4
oxygen 2.28/0.608 = 3.75
nitrogen 2.27/0.608 = 3.73
Empirical formula = CH₇O₄N₄
n=20 mol
(NH)4 SO4
Atomic masses :
N- 14
H- 1
S- 32
O- 16
Therefore M= 14×2 + 1×8 + 32 + 16×4
= 132
m= nM
= 20×132
= 2640g
The will not affect the wind. When it is windy the wind turns a turbine. Once the wind has gone through the turbine it is just normal wind, none of the wind is lost when this happened
