1.c.) vegetarian and sediment build up in the bottom hope that work's✌
3.<span>D. Since in an uplift the water descending will go even faster making it crush on the rocks with more force and more friction increasing the rate of erosion.... Helped ? :) </span>
<span>And it's true since more water makes it faster and increase in land covering
thus taking more to the sea bed :x erosion
5.</span><span>Winter – Due to an increase in snowfall
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8.</span><span>A perched water table is normally insufficient for the purpose of supplying domestic groundwater requirements and generally runs dry after it has been drilled. If a perched water table intersects a surface that has a slope, it can be manifested by seeps or springs along this line of intersection. The slope of a water table is in general proportional to the slope of the overlying land surface.
</span>13.<span>The oil could leak into your neighbors’ yards and kill the grass roots.
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14.
</span><span>Energy needed
</span>
phew im done :)
Answer: They are arranged by atomic number.
Answer:
B. SONAR (Sound Navigation Ranging)
Explanation:
Just took the test
Answer:
34.3 g
Explanation:
Step 1: Write the balanced equation
2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O
Step 2: Calculate the moles corresponding to 50.0 g of CH₃CH₂OH
The molar mass of CH₃CH₂OH is 46.07 g/mol.
50.0 g × 1 mol/46.07 g = 1.09 mol
Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced
The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.
Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced
The percent yield of the reaction is 85%.
0.545 mol × 85% = 0.463 mol
Step 5: Calculate the mass corresponding to 0.463 moles of CH₃CH₂OCH₂CH₃
The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.
0.463 mol × 74.12 g/mol = 34.3 g
According to the law of conservation of mass, the amount of BARIUM present of the reactants is the same as the amount present in the products (the precipitate).
(11.21 g BaSO4) / (233.4 g/mol BaSO4) = 0.0480 mol BaSO4 and original barium salt
(10.0 g) / (0.0480 mol) = 208.3 g/mol
So it must have been BaCl2, because the molar mass of Barium is 137 which leave 71 grams left. Since Barium is a +2 charge, it means the atom next to it must be twice. Chlorine mass is 35, which twice is 71
