Answer: 2.13 × 10⁻⁷ N
Explanation:
Gravitational force exists between any two bodies having mass.
Force of gravity is given by:
It is given that, mass of newborn baby is M = 2.50 kg
Mass of the doctor, m = 80.0 kg
Distance between the two, r = 0.250 m
Gravitational constant, G = 6.67 × 10⁻¹¹ N m²/kg²
⇒F = (6.67 × 10⁻¹¹ N m²/kg² × 2.50 kg × 80.0 kg )÷ (0.250 m)² = 2.13 × 10⁻⁷ N
Thus, the force of gravity between new born baby and doctor is 2.13 × 10⁻⁷ N.
Answer:
A) K / K₀ = 4 b) v / v₀ = 4
Explanation:
A) For this exercise we can use the conservation of mechanical energy
in the problem it indicates that the displacement was doubled (x = 2xo)
starting point. At the position of maximum displacement
Em₀ = Ke = ½ k (2x₀)²
final point. In the equilibrium position
= K = ½ m v²
Em₀ = Em_{f}
½ k 4 x₀² = K
(½ K x₀²) = K₀
K = 4 K₀
K / K₀ = 4
B) the speed value
½ k 4 x₀² = ½ m v²
v = 4 (k / m) x₀
if we call
v₀ = k / m x₀
v = 4 v₀
v / v₀ = 4