Answer:
Its either with itself to become fluoride Fl2 or with an alkali metal (elements in group 1) to achieve a stable electronic configuration or octet structure
Answer:
The value is ![L = 0.985 \pm 0.00801 \ g](https://tex.z-dn.net/?f=L%20%20%3D%20%200.985%20%5Cpm%200.00801%20%5C%20%20g)
Explanation:
From the question we are told that
The molar mass of
is ![MW = 100.085 \ g/mol](https://tex.z-dn.net/?f=MW%20%20%3D%20%20100.085%20%5C%20%20g%2Fmol)
The total mass is
The uncertainty of the total mass is ![\Delta g = 0.1](https://tex.z-dn.net/?f=%5CDelta%20g%20%20%3D%200.1)
Generally the molar weight of calcium is ![M_c = 40 g/mol](https://tex.z-dn.net/?f=M_c%20%20%3D%20%2040%20g%2Fmol)
The percentage of calcium in calcite is mathematically represented as
![C = \frac{40.07}{100.085} * 100](https://tex.z-dn.net/?f=C%20%3D%20%20%5Cfrac%7B40.07%7D%7B100.085%7D%20%2A%20100)
![C = 40.03 \%](https://tex.z-dn.net/?f=C%20%3D%20%2040.03%20%5C%25%20)
Generally the mass of each sample is mathematically represented as
![m= \frac{m_g}{5}](https://tex.z-dn.net/?f=m%3D%20%20%5Cfrac%7Bm_g%7D%7B5%7D)
![m= \frac{12.3}{5}](https://tex.z-dn.net/?f=m%3D%20%20%5Cfrac%7B12.3%7D%7B5%7D)
![m= 2.46 \ g](https://tex.z-dn.net/?f=m%3D%202.46%20%5C%20%20g%20)
Generally mass of calcium present in a single sample is mathematically represented as
![m_c = 2.46 * \frac{40.04}{100}](https://tex.z-dn.net/?f=m_c%20%3D%202.46%20%2A%20%20%5Cfrac%7B40.04%7D%7B100%7D)
![m_c = 0.985 \ g](https://tex.z-dn.net/?f=m_c%20%3D%200.985%20%5C%20%20g%20)
The uncertainty of mass of a single sample is mathematically represented as
![k = \frac{\Delta g }{5}](https://tex.z-dn.net/?f=k%20%20%3D%20%20%5Cfrac%7B%5CDelta%20g%20%7D%7B5%7D)
![k = \frac{0.1 }{5}](https://tex.z-dn.net/?f=k%20%20%3D%20%20%5Cfrac%7B0.1%20%7D%7B5%7D)
![k = 0.02\ g](https://tex.z-dn.net/?f=k%20%20%3D%20%200.02%5C%20%20g%20)
The uncertainty of mass of calcium in a single sample is mathematically represent
![G = 0.00801 \ g](https://tex.z-dn.net/?f=G%20%20%3D%20%200.00801%20%5C%20%20g%20)
Generally the average mass of calcium in each sample is
![L = 0.985 \pm 0.00801](https://tex.z-dn.net/?f=L%20%20%3D%20%200.985%20%5Cpm%200.00801)
Answer:
Ethanol
Explanation:
2 C atoms and a single OH group.
Formula: C2H5OH
Answer : The answer is,
Explanation :
Scientific notation : It is defined as the way or representation of expressing the number that are too big or too small that is written in the decimal form. That means always written in the power of 10 form.
For example : 8000 is written as,
in this notation, the significant figure is, 1 but
in this notation, the significant figures are, 2
The given problem are :
![\frac{1.8\times 10^{-2}}{9\times 10^2}=0.2\times 10^{-4}](https://tex.z-dn.net/?f=%5Cfrac%7B1.8%5Ctimes%2010%5E%7B-2%7D%7D%7B9%5Ctimes%2010%5E2%7D%3D0.2%5Ctimes%2010%5E%7B-4%7D)
According to the divide and multiplication rules of scientific figures, the final answer is only as precise as the value with the least number of significant figures.
Hence, the answer is,
0.01742919 is the answer because i worked it out