1) A
2)A
3)C
4)A
That should be all of them. Hope this helps?
Answer:
0.107 mole of SO2.
Explanation:
1 mole of a gas occupy 22.4 L at standard temperature and pressure (STP).
With the above information, we can simply calculate the number of mole of SO2 that will occupy 2.4 L at STP.
This can be obtained as follow:
22.4 L contains 1 mole of SO2.
Therefore, 2.4 L will contain = 2.4/22.4 = 0.107 mole of SO2.
Therefore, 0.107 mole of SO2 is present in 2.4 L at STP.
Answer:
I believe it would be c
Explanation:
the cold an or warm air has no effect the plant must be on it original source
Can you post the question, on here? I cant open the document.
The concentration of the hydronium ion in hydrochloric acid is 0.0045 M, and the pH of the solution is 2.34.
<h3>What is pH?</h3>
pH is the potential of the hydrogen or the hydronium ions in the aqueous solution.
As the solution contains
HCl the concentration of the hydronium ion will be the same, 
The pH of the solution is calculated as:
![\begin{aligned} \rm pH &= \rm -log[H^{+}]\\\\&= - \rm log (4.5 \times 10^{-3})\\\\&= 2.34\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20%5Crm%20pH%20%26%3D%20%5Crm%20-log%5BH%5E%7B%2B%7D%5D%5C%5C%5C%5C%26%3D%20-%20%5Crm%20log%20%284.5%20%5Ctimes%2010%5E%7B-3%7D%29%5C%5C%5C%5C%26%3D%202.34%5Cend%7Baligned%7D)
The concentration of the hydroxide ion is calculated from pH and hydronium ion as:
![\begin{aligned} \rm [H_{3}O^{+}][OH^{-}] &= 10^{-14}\\\\&= \dfrac{1 \times 10^{-14}}{4.5 \times 10^{-3}}\\\\&= 2.2 \times 10^{12}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20%5Crm%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%5BOH%5E%7B-%7D%5D%20%26%3D%2010%5E%7B-14%7D%5C%5C%5C%5C%26%3D%20%5Cdfrac%7B1%20%5Ctimes%2010%5E%7B-14%7D%7D%7B4.5%20%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5C%26%3D%202.2%20%5Ctimes%2010%5E%7B12%7D%5Cend%7Baligned%7D)
Now, for the calcium hydroxide solution, the calculations are shown as,

pOH is calculated as:
![\begin{aligned} \rm pOH &= 14- 8 = 6\\\\\rm [OH^{-}] &= \rm antilog (-6)\\\\&= 10^{-6} \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20%5Crm%20pOH%20%26%3D%2014-%208%20%3D%206%5C%5C%5C%5C%5Crm%20%5BOH%5E%7B-%7D%5D%20%26%3D%20%20%5Crm%20antilog%20%28-6%29%5C%5C%5C%5C%26%3D%2010%5E%7B-6%7D%20%5Cend%7Baligned%7D)
The concentration of calcium hydroxide is calculated as:
![\begin{aligned} &= \dfrac{1}{2} \times \rm [OH^{-}]\\\\&= 5 \times 10^{-4} \;\rm M\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20%26%3D%20%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5Crm%20%5BOH%5E%7B-%7D%5D%5C%5C%5C%5C%26%3D%205%20%5Ctimes%2010%5E%7B-4%7D%20%5C%3B%5Crm%20M%5Cend%7Baligned%7D)
Therefore, the pH and the pOH give the concentration of the hydrogen or the hydronium ion and the hydroxide ion.
Learn more about pH and pOH here:
brainly.com/question/16062632
#SPJ1