The most interesting thing about this problem is that in order to use all of the given information, you need to ignore the laws of Physics, and never mind what the stone would really do if dropped from a real bridge in the real world.
Average velocity = (displacement) / (time for the displacement)
Displacement =
Straight path from the start point to the finish point = 45 meters down .
Time = 4.6 seconds
Average velocity = 45/4.6 = <em>9.783 meters/second down</em>
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In the real world, a dropped stone would only take 3.03 seconds
to fall 45 meters.
Alternatively, a stone that fell for 4.6 seconds from rest would fall
103.7 meters, with an average velocity of 22.5 meters/second down.
But we accepted the given information, and did the best we could do
with it.
Answer:
"Apparent weight during the "plan's turn" is 519.4 N
Explanation:
The "plane’s altitude" is not so important, but the fact that it is constant tells us that the plane moves in a "horizontal plane" and its "normal acceleration" is 
Given that,
v = 420 m/s
R = 11000 m
Substitute the values in the above equation,



It has a horizontal direction. Furthermore, constant speed implies zero tangential acceleration, hence vector a = vector a N. The "apparent weight" of the pilot adds his "true weight" "m" "vector" "g" and the "inertial force""-m" vector a due to plane’s acceleration, vector
In magnitude,





Because vector “a” is horizontal while vector g is vertical. Consequently, the pilot’s apparent weight is vector

Which is quite heavier than his/her true weigh of 519.4 N
Answer:
Jim's kinetic energy is 54.67 J.
Explanation:
Given that,
Mass, m = 15 kg
Velocity, V = 2.7 m/s
We need to find the Jim's kinetic energy. We know that when the object is in motion, it has kinetic energy. This energy is given by :


E = 54.67 J
So, Jim's kinetic energy is 54.67 J. Hence, this is the required solution.
Answer:
C₁ = 3 pF
C₂ = 6 pF
Explanation:
Let the capacitance be C₁ and C₂.
For parallel combination
C₁ +C₂ = 9
For series combination


C₁ X C₂ = 18
( 9-C₂ )X C₂ = 18
C₂²- 9C₂ +18 = 0
C₂ = 6 or 3.
C₁ = 3 or 6.
C₁ = 3 pF
C₂ = 6 pF