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3 years ago

A wave is traveling through X. What can be known about X?

Physics

2 answers:

zhuklara [117]3 years ago

5 0

X can probably be vacuum through space through air and or solid objects

luda_lava [24]3 years ago

4 0

Answer:

solid

Explanation:

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A man 6.00 ft tall approaches a street light 15.0 ft above the ground at the rate of 4.00 ft/s. How fast is the end of the man

klio [65]

Answer:

$\frac{dx}{dt} = 10 ft/s$

Explanation:

As per given figure let say the tip of the shadow is at distance "x" from the base of the lamp

so here we have

$\frac{x}{15} = \frac{x - y}{6}$

so we have

$6x = 15 x - 15 y$

$15 y = 9 x$

now we have

$5\frac{dy}{dt} = 2\frac{dx}{dt}$

$5(4) = 2\frac{dx}{dt}$

$\frac{dx}{dt} = 10 ft/s$

7 0

4 years ago

List the chemicals and apparatus

Softa [21]

Answer:

Beaker

Graduated Cylinders

Volumetric flask

Test tube

Funnel

4 0

2 years ago

PLEASE HELP!<br> QUESTION 2A,B and C. PLEASE HELP. 50 points

Greeley [361]

Answer:

first

Explanation:

7 0

4 years ago

- A capacitor's dielectric material is a vacuum. The capacitor's dielectric constant, or K, will be equal to

dlinn [17]

If a capacitor's dielectric constant is vacuum its dielectric constant is k will be equal to 1.

<u>Explanation:</u>

Relative permittivity of a dielectric substance is referred to as its dielectric constant. Relative permittivity/dielectric constant k is a dimensionless quantity that is the ratio of absolute permittivity and vacuum permittivity.

It is given by the expression

k=k=ε /ε0

where ε denotes absolute permittivity and ε0 denotes permittivity of vacuuum.

Absolute permittivity ε of vacuum= ε0

therefore k= ε0/ ε0=1

dielectric constant of vacuum is 1 .

4 0

3 years ago

A gold bar has a density of 19.3 g/mL. If the gold bar has a mass of 6.3 grams, what is the volume?

Natali [406]

Answer:

The correct answer is "0.32 mL".

Explanation:

The given values are:

Density of gold bar,

d = 19.3 g/mL

Mass of gold bar,

m = 6.3 grams

Now,

The volume will be:

⇒ $Density = \frac{Mass}{Volume}$

or,

⇒ $Volume=\frac{Mass}{Density}$

On substituting the values, we get

⇒ $=\frac{6.3 \ g}{19.3 \ g/mL}$

⇒ $=0.32 \ mL$

7 0

3 years ago