A wave is traveling through X. What can be known about X?

Physics

2 answers:

zhuklara [117]3 years ago

5 0

X can probably be vacuum through space through air and or solid objects

luda_lava [24]3 years ago

4 0

Answer:

solid

Explanation:

You might be interested in

A stone is dropped from a bridge 45 meters above the surface river. It takes the stone 4.6 seconds to reach the water surface. F

Hunter-Best [27]

The most interesting thing about this problem is that in order to use all of the given information, you need to ignore the laws of Physics, and never mind what the stone would really do if dropped from a real bridge in the real world.

Average velocity = (displacement) / (time for the displacement)

Displacement =
Straight path from the start point to the finish point = 45 meters down .
Time = 4.6 seconds

Average velocity = 45/4.6 = <em>9.783 meters/second down</em>

==================================

In the real world, a dropped stone would only take 3.03 seconds
to fall 45 meters.

Alternatively, a stone that fell for 4.6 seconds from rest would fall
103.7 meters, with an average velocity of 22.5 meters/second down.

But we accepted the given information, and did the best we could do
with it.

7 0

3 years ago

Read 2 more answers

(BRAINLIEST)

tankabanditka [31]

Cm=C
Gram=G
s=S

ITs CGS unit.

Hence

CGS unit of Joules is erg.
1J=1×10^7ergs

$\\ \sf\longmapsto 15J=15\times 10^7ergs$

4 0

3 years ago

Read 2 more answers

A fighter plane flying at constant speed 420 m/s and constant altitude 3300 m makes a turn of curvature radius 11000 m. On the g

Arada [10]

Answer:

"Apparent weight during the "plan's turn" is 519.4 N

Explanation:

The "plane’s altitude" is not so important, but the fact that it is constant tells us that the plane moves in a "horizontal plane" and its "normal acceleration" is $\mathrm{a}_{\mathrm{n}}=\frac{v^{2}}{R}$

Given that,

v = 420 m/s

R = 11000 m

Substitute the values in the above equation,

$a_{n}=\frac{420^{2}}{11000}$

$a_{n}=\frac{176400}{11000}$

$a_{n}=16.03 \mathrm{m} / \mathrm{s}^{2}$

It has a horizontal direction. Furthermore, constant speed implies zero tangential acceleration, hence vector a = vector a N. The "apparent weight" of the pilot adds his "true weight" "m" "vector" "g" and the "inertial force""-m" vector a due to plane’s acceleration, vector $W_{\mathrm{app}}=m(\text { vector } g \text { -vector a })$