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Setler [38]
4 years ago
6

In the graph, during which time period does the particle undergo the greatest displacement?

Physics
1 answer:
VMariaS [17]4 years ago
5 0
I'm not very good with Physics but of what I do know I'd go with point                   B / 4seconds 

I apologize in advance if that is incorrect.
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A cable passes over a pulley. Because the cable grips the pulley and the pulley has nonzero mass, the tension in the cable is no
topjm [15]

Answer:

\alpha=214.8 rad/s^2

Explanation:

We are given that

F_1=137 N

F_2=43 N

Net force=F=F_1-F_2=137-43=94 N

Mass,m=1.21 kg

Radius,r=0.723 m

We have to find the magnitude of its angular acceleration.

Moment of inertia ,I=\frac{1}{2}mr^2

Substitute the values

Torque ,\tau=I\alpha

F_{net}\times r=\frac{1}{2}mr^2\alpha

\alpha=\frac{2F_{net}}{mr}

\alpha=\frac{2\times 94}{1.21\times 0.723}

\alpha=214.8 rad/s^2

4 0
3 years ago
A 770 n man stands in the middle of a frozen pond of radius 10.0 m. he is unable to get to the other side because of a lack of f
oksano4ka [1.4K]
Momentum is conserved throughout this scenario.

Before the man does anything, the total momentum of him and his book is zero.  So we know that it'll be zero after he throws the book.

Momentum = (mass) x (velocity)

The man gives the book (1.2 kg)x(10 m/s north) = 12 kg-m/s north
of momentum.

Since the total momentum must be zero, the man himself picks up 120 kg-m/s of momentum south.

(his mass)x(his v) = 120 kg-m/s south = (770 kg-m/s^2/9.8 m/s^2)x(V).

His velocity southward = (120 x 9.8) / (770)    m/s .

He needs to reach the shore 10m away.

Time = distance/speed

        =  (10 x 770) / (120 x 9.8) seconds

        =  6.55 seconds 


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3 years ago
What are two reasons why a home computer scanner requires
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Answer: C and D

Explanation: a p e x

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One of the two daughter cells wouldn't have a nucleus, which would result in the death of that cell, if not both. Hope this helps! ❤️
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If a shot is put an angle of 41 degrees relative to the horizontal with a velocity of 36 ft/s in the direction of the put, what
Anarel [89]
Idk no idea none zero sorry hope someone know more than me
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