The probability that a 2 or 3 is rolled at least once is 0.14.
<h3>
Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>
when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.
rolling a six sided die two times, p(2 or 3)' = 11/12
rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144
the probability that a 2 or 3 is rolled at least once is calculated as follows;
P = 1 - p(2 or 3)'
P = 1 - 121/144
P = 20/144
P = 0.14
Thus, the probability that a 2 or 3 is rolled at least once is 0.14.
Learn more about probability here: brainly.com/question/24756209
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Answer:
Step-by-step explanation:
<h3><u>Given:</u></h3>
y = 12 cm
θ = 24°
Using trigonometric ratio, tan.
![\displaystyle \boxed{tan \theta = \frac{opposite}{adjacent} }\\\\tan \ 24 = \frac{x}{12} \\\\0.445 = \frac{x}{12} \\\\Multiply \ 12 \ to \ both \ sides\\\\0.445 \times 12 = x\\\\5.3 = x\\\\x = 5.3\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboxed%7Btan%20%5Ctheta%20%3D%20%5Cfrac%7Bopposite%7D%7Badjacent%7D%20%7D%5C%5C%5C%5Ctan%20%5C%2024%20%3D%20%5Cfrac%7Bx%7D%7B12%7D%20%5C%5C%5C%5C0.445%20%3D%20%5Cfrac%7Bx%7D%7B12%7D%20%5C%5C%5C%5CMultiply%20%5C%2012%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C0.445%20%5Ctimes%2012%20%3D%20x%5C%5C%5C%5C5.3%20%3D%20x%5C%5C%5C%5Cx%20%3D%205.3%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
12/9
every friend gets 1 1/3 pounds of pecans
