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aalyn [17]
3 years ago
14

"a horn emits a frequency of 1000 HZ. A 14 m/s wind is blowing toward a listener. What is the frequency of the sound heard by th

e listener
Physics
1 answer:
Semenov [28]3 years ago
7 0

Answer:

 f_L = 1000 Hz

Explanation:

given,

speed of wind, = 14 m/s

frequency of horn,f_s = 1000 Hz

speed of sound,V = 344 m/s

frequency heard by the listener

using Doppler effect

f_L = \dfrac{v+v_L}{v+v_s}f_s

f_L is the frequency of the sound heard by the listener

f_s is the frequency of sound emitted by the listener

V is the speed of sound

v_L is the speed of listener

v_s is the speed of source

now,

considering the frame of reference in which wind is at rest now, both listener and the source will be moving at 14 m/s

 f_L = \dfrac{v+14}{v+14}\times 1000

now on solving we will get

 f_L = 1000 Hz

hence, the frequency heard by the listener is equal to  1000 Hz

 

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Answer:

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Explanation:

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As per the question, 'any change in the initial velocity of the projectile(object having gravity as the only force) would lead to a change in the range as well as the maximum height of the projectile.' To illustrate numerically:

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the maximum distance also depends upon square of the initial velocity.

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3 years ago
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Answer:

F = 479.21 N

Explanation:

given,

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tension in the hitch = ?          

using equation of motion          

v = u + a t

16.7 = 0 + a × 20.7

a = 0.807 m/s²              

Force = mass × acceleration        

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F = 479.21 N

Hence, the tension in the hitch that connects the  trailer to the car is        F = 479.21 N

7 0
3 years ago
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Answer:

6.25 ms²

Explanation:

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3 0
2 years ago
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3 years ago
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