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Gekata [30.6K]
3 years ago
11

What does the left y-axis show?

Physics
1 answer:
vivado [14]3 years ago
6 0

Answer:

The correct option is;

a- sea surface temperature anomaly, in degrees Celsius

Explanation:

From the diagram related to the question we have two graphs super imposed of Sea surface temperature anomaly, in degrees Celsius and cholera incidence anomaly (%) both plotted against time in years.

On the left the y-axis represents the sea surface temperature anomaly while on the right, the y-axis represents the cholera incidence anomaly (%).

The display of the graph shows the sea surface temperature anomaly in blue.

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Assume that a resistor is connected between the 150 V terminal and the common terminal. The voltmeter is then connected to an un
Lena [83]

Answer: 316.8V

Explanation:

given data:

metre moving current = 0.96mA

meters voltage = 288V

or  0.96*300V = 288V

<u><em>Solution:</em></u>

<u><em /></u>v1 = (0.96mA*150)<u><em /></u>

<u><em /></u>= 144V<u><em /></u>

<u><em /></u>

i1 = \frac{144v}{750}

= 0.192mA

i2 = imovement + i1

i2= 0.96mA+0.192mA

= 1.152mA

Vmeasured = 144V+(150)(1.152mA)

=316.8V

the unknown voltage is 316.8V

7 0
3 years ago
A book is moved once around the edge of a tabletop with dimensions 1.75 m à 2.25 m. If the book ends up at its initial position,
uysha [10]

Explanation:

The dimension of the book is 1.75 m × 2.25 m. If the book ends up at its initial position. The displacement of the book is equal to zero as the object reaches to its initial position.

If it completes its motion in 23 s, t = 23 s

Total displacement of the book is equal to its perimeter. It is given by :

d=2(1.75+2.25)=8\ m

The net displacement divided by total time taken is called the average velocity of an object. Here, the displacement is 0. So, average velocity is 0.

The average speed of an object is given by :

v=\dfrac{d}{t}

v=\dfrac{8\ m}{23\ s}

v = 0.347 m/s

So, the average speed of the book is 0.347 m/s. Hence, this is the required solution.

6 0
3 years ago
Consider a semi-spherical bowl machined out of wood (A drawing of a semi-spherical bowl can be found in UNIT- 4 Introduction, so
Mrrafil [7]

Answer:

The total surface are of the bowl is given by: 0.0532*pi m² (approximately 0.166533 m²)

Explanation:

The total surface area of the semi-spherical bowl can be decomposed in three different sections: 1) an outer semi-sphere of radius 12 cm, 2) an inner semi-sphere of radius 10 cm, and 3) the edge, which is a 2-dimensional ring with internal radius of 10 cm and external radius of 12 cm. We will compute the areas independently and then sum them all.

a) Outer semi-sphere:

A1 = 2*pi*r² = 2*pi*(12 cm)² = 288*pi cm² = 904.78 cm²

b) Inner semi-sphere:

A2 = 2*pi*(10 cm)² = 200*pi cm² = 628.32 cm²

c) Edge (Ring):

A3 = pi*(r1² - r2²) = pi*((12 cm)²-(10 cm)²) = pi*(144-100) cm² = 44*pi cm² = 138.23 cm²

Therefore, the total surface area of the bowl is given by:

A = A1 + A2 + A3 = 288*pi cm² + 200*pi cm² + 44*pi cm² = 532*pi cm² (approximately 1665.33 cm²)

Changing units to m², as required in the problem, we get:

A = 532*pi cm² * (1 m² / 10, 000 cm²) = 0.0532*pi m² (approximately 0.166533 m²)

5 0
3 years ago
PLEASE HURRYYYY!!!<br><br> Explain how you read measurements in a graduated cylinder?
fredd [130]

Answer:

Reading a Graduated Cylinder

Place the graduated cylinder on a flat surface and view the height of the liquid in the cylinder with your eyes directly level with the liquid. The liquid will tend to curve downward. This curve is called the meniscus. Always read the measurement at the bottom of the meniscus.....

hope it helps....

5 0
1 year ago
A 20 kg wagon is rolling to the right across a floor. A person attempts to catch and stop the crate and applies a force of 70 N,
Serggg [28]

Answer:

1.736m/s²

Explanation:

According to Newton's second law;

\sum F_x = ma_x\\

Fm - Ff = ma_x\\ where;

Fm is the moving force = 70.0N

Ff is the frictional force acting on the body

Ff = \mu R\\Ff = \mu mg\\

\mu is the coefficient of friction

m is the mass of the object

g is the acceleration due to gravity

a is the acceleration/deceleration

The equation becomes;

Fm - Ff = ma_x\\Fm - \mu mg = ma\\

Substitute the given parameters

Fm - \mu mg = ma\\70 - 0.18(20)(9.8) = 20a\\70-35.28 = 20a\\34.72 = 20a\\a = \frac{34.72}{20}\\a =  1.736m/s^2\\

Hence the deceleration rate of the wagon as it is caught is 1.736m/s²

7 0
3 years ago
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