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Nataliya [291]
3 years ago
15

Is time a vector, scalar, both, neither

Physics
1 answer:
disa [49]3 years ago
5 0

Answer:

neither

Explanation:

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The velocity time graph of an object is shown below. How far does the object travel in the time interval t =4 s to t = 6 s?
Trava [24]

The distance covered by the object between t =4 s and t = 6 s is 4 m

Explanation:

In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.

Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.

We see that we have to calculate the area of a triangle, with:

Base:

b=6-4 = 2

And height:

h=4-0 = 4

Therefore, the area is

A=\frac{1}{2}bh=\frac{1}{2}(2)(4)=4

So, the distance covered by the object is 4 m.

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

3 0
4 years ago
Una ardilla corre desarrollando una aceleracion de 3.5 m/s2 la fuerza ejecidas por las patas traseras es de 5 N. Cual sera la ma
ziro4ka [17]

Answer:

1.43 kg

Explanation:

We can solve the problem by using Newton's second law:

F=ma

where

F is the net force on an object

m is its mass

a is its acceleration

For the squirrel in the problem, we have:

a=3.5 m/s^2 is the acceleration

F = 5 N is the net force acting on it

Solving for m, we find its mass:

m=\frac{F}{a}=\frac{5}{3.5}=1.43 kg

4 0
3 years ago
6. Which is a characteristic of the observant function?
nlexa [21]

Focusing on the present is a characteristic of the observant function.

<h3>What is an Observant personality trait?</h3>

This trait is characterized by people who pay much attention to themselves more than others.

This type of people focus on the present and ensure things are done without procrastination. This depicts the option D which makes it the most appropriate choice.

Read more about Observant trait here brainly.com/question/12283441

7 0
2 years ago
A pendulum is used in a large clock. The pendulum has a mass of 2 kg. If the pendulum is moving at a speed of 2.9 m/s when it re
Rufina [12.5K]
This is a classic example of conservation of energy. Assuming that there are no losses due to friction with air we'll proceed by saying that the total energy mus be conserved.
E_m=E_k+E_p
Now having information on the speed at the lowest point we can say that the energy of the system at this point is purely kinetic:
E_m=Ek=\frac{1}{2}mv^2
Where m is the mass of the pendulum. Because of conservation of energy, the total energy at maximum height won't change, but at this point the energy will be purely potential energy instead.
E_m=E_p
This is the part where we exploit the Energy's conservation, I'm really insisting on this fact right here but it's very very important, The totam energy Em was
E_M=\frac{1}{2}mv^2
It hasn't changed! So inserting this into the equation relating the total energy at the highest point we'll have:
E_p=mgh=E_m=\frac{1}{2}mv^2
Solving for h gives us:
h=\frac{v^2}{2g}.
It doesn't depend on mass!

4 0
3 years ago
Read 2 more answers
.A 0.2-kg aluminum plate, initially at 20°C, slides down a 15-m-long surface, inclined at a 30 angle to the horizontal. The forc
Ainat [17]

To solve this problem, it is necessary to apply the concepts related to Work according to the Force and distance, as well as the concepts related to energy lost-or gained-by heat. Mathematically the energy corresponding to heat is given as:

Q = mC_p(\Delta T)

Where,

m = mass

C_p= Specific heat

\Delta T = Change in Temperature

At the same time the Work made by the Force and the distance is given as:

W = F*d \rightarrow W=mg*d

As the force is applied at an angle of 30 degrees, the efficient component would be given by the vertical then the work / energy would be determined as:

W = mg*dsin(30)

W = (15m)(0.2kg)(9.81)(sin30)

W = 13.24J

Now this energy is used to heat the aluminum. We can find the change at the temperature as follow:

Q = mC_p(\Delta T)

13.24 = (0.2)(900)(\Delta T)

\Delta T = 0.0736 \°C

Therefore the correct answer is B.

7 0
3 years ago
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