Answer: 2700 Joules
Explanation:
Given variables are:
Workdone (w) = ?
Weight of sack (w) = 15N
Time taken (t) = 3 minutes
The standard unit of time is seconds, so convert 3 minutes to seconds
(If 1 minute = 60 seconds
3 minutes = 3 x 60 = 180 seconds)
Recall that work is done is when force is applied on an object over a distance
i.e Workdone = force x distance.
(However, the force acting on the sack of potatoes is weight)
Hence, workdone = weight x time
w = 15N x 180 seconds
w = 2700 J
thus, 2700 joules of work was done.
Answer:
ΔR = 9 s
Explanation:
To calculate the propagation of the uncertainty or absolute error, the variation with each parameter must be calculated and the but of the cases must be found, which is done by taking the absolute value
The given expression is R = 2A / B
the uncertainty is ΔR = | 
| ΔA + | 
| ΔB
we look for the derivatives
= 9 / B
= 9A ( 
)
we substitute
ΔR = 
ΔA + 
ΔB
the values are
ΔA = 2 s
ΔB = 3 s
ΔR = 
2 + 
3
ΔR = 1.636 + 7.14
ΔR = 8,776 s
the absolute error must be given with a significant figure
ΔR = 9 s
Answer:
Explanation:
a )
Amplitude A = 14 mm , angular frequency ω = 2π / T
= 2π / .5
ω = 4π rad /s
φ₀ = initial phase
Putting the given values in the equation
14 = 25 cos(ωt + φ₀ )
14/25 = cosφ₀
φ₀ = 56 degree
x(t) = 25cos(4πt + 56° )
b )
maximum velocity = ω A
= 4π x 25
100 x 3.14 mm /s
= 314 mm /s
At x = 0 ( equilibrium position or middle point , this velocity is achieved. )
maximun acceleration = ω² A
= 16π² x A
= 16 x 3.14² x 25
= 3943.84 mm / s²
3.9 m / s²
It occurs at x = A or at extreme position.
Answer:
85.9 V
Explanation:
The voltage across C₃ is 40.0 V, so the voltage between a and d must also be 40.0 V.
Find the equivalent capacitance of C₁, C₂, and C₃:
C₁₂₃ = 1 / (1/C₁ + 1/C₂) + C₃
C₁₂₃ = 1 / (1/8.00 + 1/7.00) + 2.00
C₁₂₃ = 5.73 mF
This is in series with C₄. Capacitors in series have the same charge, so:
Vad C₁₂₃ = Vbd C₄
(40.0) (5.73) = Vbd (5.00)
Vbd = 45.9 V
The total voltage is therefore:
V = Vad + Vbd
V = 40.0 + 45.9
V = 85.9 V
Vo = 18m/s
Vt = 0 -> cause speed boat will stop in 8 s
m = 1550kg
t= 8s
F,,???/
Vt = Vo - a.t
0 = 18 - a.8
18 = a8
a=2,25m/s^2
F = m.a
F = 1550 . 2,25
F =3487,5N
