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REY [17]
3 years ago
9

Question 26 (1 Point)

Physics
2 answers:
Mekhanik [1.2K]3 years ago
5 0

Answer:

Idk

Explanation:

Please help me no cap

LUCKY_DIMON [66]3 years ago
4 0

The book continue to move due to its inertia

Explanation:

We can answer this question by using Newton's first law, which states that:

"When an object is moving with constant velocity (or it is at rest), it will continue moving with constant velocity (or will stay at rest) unless acted upon an external unbalanced force".

This law is also known as law of inertia.

If we apply this law to the situation in the problem, we notice that:

- Before the car stops, the book is moving with constant velocity (25 mph) together with the car

- When the car stops, there are no external forces acting on the book, which is free to continue its motion: so, the book will continue moving at 25 mph forward, due to its inertia. The book will be eventually stopped when it hits the floor (because the floor applies an unbalanced force on it).

Learn more about inertia:

brainly.com/question/2286502

brainly.com/question/691705

#LearnwithBrainly

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you are riding on a train traveling 80 km/h. if you walk toward the back of the train at a speed of 1.2 km/h relative to the tra
Mazyrski [523]

Answer:

Velocity of the passenger = 78.8[km/h]

Explanation:

In order to solve this problem, we must observe the train from a distant point of the train. In this way we can observe that the train moves at 80[km/h] relative to the ground.

In such a way that the passenger moves in a direction contrary to the movement of the train.

v_{pass}=80-1.2\\ v_{pass}=78.8[km/h]

The Observer located outside the train will see how the passenger moves away at 78.8 [km / h] and not at 80[km/h] which is the speed of the train.

6 0
3 years ago
A moving walkway at the airport moves a 120Kg person 35m in 150s. How much power did this require?
Alexxx [7]

The amount of power required to move the 120 Kg person to a distance of 35 m in 150 s is 274.4 W

<h3>How to determin the power</h3>

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = force (F) × distance (d)

Therefore,

P = Fd / t

With the above formula, we can obtain the power as follow:

  • Mass (m) = 120 Kg
  • Distance (d) = 35 m
  • Time (t) = 150 s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Force (F) = mg = 120 × 9.8 = 1176 N
  • Power (P) = ?

P = Fd / t

P = (1176 × 35) / 150

P = 41160 / 150

P = 274.4 W

Thus, the power is 274.4 W

Learn more about power:

brainly.com/question/20353916

#SPJ1

6 0
1 year ago
Determine the critical crack length for a through crack contained within a thick plate of 7150-T651 aluminum alloy that is in un
Mila [183]

Explanation:

Formula to determine the critical crack is as follows.

          K_{IC} = \gamma \sigma_{f} \sqrt{\pi \times a}

  \gamma = 1,     K_{IC} = 24.1

  [/tex]\sigma_{y}[/tex] = 570

and,   \sigma_{f} = 570 \times \frac{3}{4}

                       = 427.5

Hence, we will calculate the critical crack length as follows.

      a = \frac{1}{\pi} \times (\frac{K_{IC}}{\sigma_{f}})^{2}

        = \frac{1}{3.14} \times (\frac{24.1}{427.5})^{2}

       = 10.13 \times 10^{-4}

Therefore, largest size is as follows.

            Largest size = 2a

                                 = 2 \times 10.13 \times 10^{-4}

                                 = 20.26 \times 10^{-4}

Thus, we can conclude that the critical crack length for a through crack contained within the given plate is 20.26 \times 10^{-4}.

4 0
3 years ago
3. A 65 kg runner exerts a force of 59N. What is the acceleration of the<br> runner?
Mandarinka [93]

Answer:

<h2>1.10 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{65}{59}  \\  = 1.101694...

We have the final answer as

<h3>1.10 m/s²</h3>

Hope this helps you

7 0
3 years ago
What is the change in velocity of a 15 kg object that experiences a 5 N force for 0.3 seconds?
alukav5142 [94]

Hello!

Δv = 0.1 m/s

Use the equation F = m · a to solve for the acceleration:

5 = 15 · a

a = 1/3

The equation to solve for acceleration can be rewritten to solve for the change in velocity:

Δv / t = a

Δv = at

We are given the acceleration and time, therefore:

Δv = (1/3)(0.3)

Δv = 0.1 m/s

3 0
3 years ago
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