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jonny [76]
3 years ago
10

Apples are stored in a container (width = length = 3.5 ft) that is filled to a depth of 2.75 feet. If the unit density of an app

le is 49.3 lb/ft^3 and porosity is 31%, how many pounds of apples are in the box? Show work please.
Physics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

The mass of the apples in the box are 1145.95 lb.

Explanation:

Given that,

Width = 3.5 ft

length = 3.5 ft

Depth = 2.75 feet

Density = 49.3 lb/ft³

We need to calculate the volume

Using formula of volume

V=l\times h\times b

Put the value

V=3.5\times3.5\times2.75

V=33.6875\ ft^3

We need to calculate the mass

Using formula of density

\rho=\dfraxc{m}{V}

m=\rho\timesV

Put the value into the formula

m=49.3\times33.6875

m=1660.79\ lb

But porosity is 31 % so apples is 69% mass of total container.

So, Total mass in pounds is

M=\dfrac{69}{100}\times1660.79

M=1145.95\ lb

Hence, The mass of the apples in the box are 1145.95 lb.

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The focal length of a lens is inversely proportional to the quantity (n-1), where n is the index of refraction of the lens of th
Ainat [17]

Answer:

46.22 cm

Explanation:

The focal refraction, fr is given by

fr = \frac {c}{(1.572 -1)}  = \frac {c}{0 .572}  

The focal red light is given by

fv = \frac {c}{(1.605 - 1)} = \frac {c}{0.605}

\frac {fv}{fr} = \frac {0.572}{0 .605} = 0.945455

\frac {1}{fr} = \frac{1}{image} + \frac {1}{object} and making fr the subject we obtain

fr = \frac {image * object}{(image + object)} = \frac {24.00 * 55} {(24.0 + 55)} = 16.70886 cm

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5 0
4 years ago
What is approximate resistance between P and Q?<br> a) 0.5<br> b)0.8<br> c)2.0<br> d)2.2<br> e)3.6
Rufina [12.5K]

Answer:

0.5 Ohms

Explanation:

We note that the node Q is also between the resistors of 1ohm and 2ohms.

We note that the node P is also between the resistors of 2ohms and 3ohms.

Thus, all these resistors are in parallel, beween nodes P and Q

1/Re=1/R1+1/R2+1/R3

1/Re=1/1+1/2+1/3=(6+3+2)/6=11/6 [ohm^(-1)]

Re=6/11=0.54ohms

Rounding to the tenth: Re=0.5 ohms

8 0
3 years ago
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Answer:

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Explanation:

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where f is the focal length, n₂ is the refractive index of the material, n₀ is the refractive index of the medium surrounding the material, R₁ and R₂ are the radius of curvature of each of the material's

In our case, the most common is that the lens is in the air, so n1 = 1, in many cases one of the surfaces is flat, so its radius of curvature R₂ = ∞.

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we look for the radius of curvature R₁

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