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zlopas [31]
3 years ago
14

Find the original concentration of a solution diluted from 15.00 mL to 125.0 mL with a final concentration of 0.00383 M

Chemistry
1 answer:
BabaBlast [244]3 years ago
8 0
<h3>Answer:</h3>

0.03192 M

<h3>Explanation:</h3>

We are given;

  • Initial volume before dilution, V1 = 15.0 mL or 0.015 L
  • Volume after dilution, V2 = 125.0 mL or 0.125 L
  • Concentration after dilution, M2 = 0.00383 M

We are required to calculate the initial concentration, M1 before dilution.

  • To answer the question, we will use the dilution formula;
  • Dilution formula is given by; M1V1 = M2V2

Rearranging the formula;

M1 = M2V2 ÷ V1

    = ( 0.00383 M × 0.125 L) ÷ 0.015 L

   = 0.03192 M

Therefore, the original concentration of the solution before dilution is 0.03192 M

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