Question

Find the original concentration of a solution diluted from 15.00 mL to 125.0 mL with a final concentration of 0.00383 M

Answer 1

Answer:

0.03192 M

Explanation:

We are given;

• Initial volume before dilution, V1 = 15.0 mL or 0.015 L
• Volume after dilution, V2 = 125.0 mL or 0.125 L
• Concentration after dilution, M2 = 0.00383 M

We are required to calculate the initial concentration, M1 before dilution.

• To answer the question, we will use the dilution formula;

• Dilution formula is given by; M1V1 = M2V2

Rearranging the formula;

M1 = M2V2 ÷ V1

    = ( 0.00383 M × 0.125 L) ÷ 0.015 L

   = 0.03192 M

Therefore, the original concentration of the solution before dilution is 0.03192 M