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zlopas [31]
2 years ago
14

Find the original concentration of a solution diluted from 15.00 mL to 125.0 mL with a final concentration of 0.00383 M

Chemistry
1 answer:
BabaBlast [244]2 years ago
8 0
<h3>Answer:</h3>

0.03192 M

<h3>Explanation:</h3>

We are given;

  • Initial volume before dilution, V1 = 15.0 mL or 0.015 L
  • Volume after dilution, V2 = 125.0 mL or 0.125 L
  • Concentration after dilution, M2 = 0.00383 M

We are required to calculate the initial concentration, M1 before dilution.

  • To answer the question, we will use the dilution formula;
  • Dilution formula is given by; M1V1 = M2V2

Rearranging the formula;

M1 = M2V2 ÷ V1

    = ( 0.00383 M × 0.125 L) ÷ 0.015 L

   = 0.03192 M

Therefore, the original concentration of the solution before dilution is 0.03192 M

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To name the compound written as CuCl2, you would write:
vovangra [49]

Answer: option C. Copper (II) chloride

Explanation:

To name CuCl2, we need to know the oxidation state of Cu in the compound as chlorine always have oxidation on —1 in all its compound. The oxidation state of Cu can be calculated as follows:

Cu + 2Cl = 0 (since the compound has no charge)

Cl = —1

Cu + 2(—1) = 0

Cu —2 = 0

Collect like terms

Cu = 0 +2

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4 0
2 years ago
A gas at 400 k is placed in a 4.0 l moveable piston. The gas is cooled to 252 k. What is the new volume of the piston?
katrin [286]

Answer:

2.52L

       

Explanation:

Given parameters:

T₁  = 400K

V₁  = 4L

T₂ = 252K

unknown

V₂ = ?

Solution:

To solve this problem, we are going to apply charle's law. The law states that the volume of a fixed mass of gas is directly proportional to temperature provided pressure is constant.

Mathematically,

               \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

Substitute and solve for V₂

           \frac{4}{400}  = \frac{V_{2} }{252}

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6 0
3 years ago
Convert the following with the correct number of significant figures:
larisa [96]

Answer:

1.78 × 10⁹ μg

Explanation:

We have to convert 1.78 kg to μg.

Step 1: Convert 1.78 kilograms to grams

We will use the conversion factor 1 kg = 10³ g.

1.78 kg × 10³ g/1 kg = 1.78 × 10³ g

Step 2: Convert 1.78 × 10³ grams to micrograms

We will use the conversion factor 1 g = 10⁶ μg.

1.78 × 10³ g × 10⁶ μg/1 g = 1.78 × 10⁹ μg

8 0
2 years ago
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