Because in a smaller container, there is less room for the gas to exist. the gas much all push together closer to fit in the smaller container. as gas atoms, they have less room to bounce around. in a bigger container, it has more room to more and is less pressurized
I feel like it is important, because it is always nice to learn about
new things and keep your mind open, to expand your knowledge.
I hope this helps ^-^
Answer:
See explanation
Explanation:
From the analysis we have in the question, we must look towards a first row transition metal ion having a d^6 configuration because it yields a paramagnetic complex having four unpaired electrons and a diamagnetic complex having no unpaired electrons.
We have two possible candidates in mind, Fe^2+ and Co^3+. However, Fe^2+ does not form as many coloured complexes as stated in the question so we have to eliminate that option.
We are now left with only Co^3+. Various ligands are going to cause these various colours of Co^3+ to appear in solution.
Hence, we can deduce from all these that the nature of ligands determines the colour of the complex . Don't forget that the colour of a complex arises from crystal field splitting.
Answer:
A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C
Explanation:
A₃B₈ + C₂ –> AC₂ + B₂C
The equation can be balance as illustrated below:
A₃B₈ + C₂ –> AC₂ + B₂C
There are 3 atoms of A on the left side and 1 atom on the right side. It can be balance by writing 3 before AC₂ as shown below:
A₃B₈ + C₂ –> 3AC₂ + B₂C
There are 8 atoms of B on the left side and 2 atoms on the right side. It can be balance by writing 4 before B₂C as shown below:
A₃B₈ + C₂ –> 3AC₂ + 4B₂C
There are 2 atoms of C on the left side and a total of 10 atoms on the right side. It can be balance by writing 5 before C₂ as shown below:
A₃B₈ + 5C₂ –> 3AC₂ + 4B₂C
Now, the equation is balanced.
Low pH = high acidity.
HF has a very low pH, so when added to a solution, it will lower the pH of the solution and therefore make it more acidic. So the answer should be B.
