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3 years ago

If cos∠A=3421,000, then what is m∠A to the nearest degree?

Mathematics

2 answers:

rjkz [21]3 years ago

6 0

Answer:

It would be 70 degrees

Step-by-step explanation:

lana66690 [7]3 years ago

3 0

Wow ! That's some cosine !
No angle has a cosine greater than ' 1 '.
The question has no answer.

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Rewrite with positive exponents: 7^-3

Advocard [28]

Answer:

1/7^3 (One over seven thirds)

Step-by-step explanation:

3 0

2 years ago

a cold wave hit chicago when the temperature hit 62 f during the cold wave the temperature dropped 2 degrees every hour how many

Vladimir [108]

We start at 62 Fahrenheit. And every hour we drop two degrees. We want to know how long it took for the temperature to drop to 40 Fahrenheit.

If one hour passed, then the temperature dropped two degrees.
If two hours passed, then the temperature dropped 4 degrees.

See the pattern? We can define this as 2h. Where h represents time in hours.
We subtract 2h from 62.

We can write this as a function. F(h) = 62 - 2h.
Where F is the temperature in Fahrenheit. And h is the hour(s).

Now that we have the formula, let's plug in the value 40 Fahrenheit to see how long it took for the temperature to drop to 40 degrees.

40 = 62 - 2h
Subtract 62 from each side

-22 = -2h
Divide both sides by 2

h = 11

So, it took 11 hours for the temperature to drop to 40 Fahrenheit.

3 0

2 years ago

PLEASE HELP IT"S DUE IN 20 MINS!!!

BlackZzzverrR [31]

Answer:

the available molding is not enough the molding is 1 inch shorter

Step-by-step explanation:

convert 13 feet into inches then add the 9 inches

7 0

2 years ago

What is the solution to the system of equations?

frez [133]

(-19,55) x is equal to -19 and y is equal to 55

4 0

3 years ago

Read 2 more answers

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream. What is the rate of

nikitadnepr [17]

<h3>Rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr</h3><h3><u>Solution:</u></h3>

Given that,

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream

Therefore,

Upstream distance = 165 km

Upstream time = 3 hours

<h3><u>Find upstream speed:</u></h3>

$speed = \frac{distance}{time}\\\\speed = \frac{165}{3}\\\\speed = 55$

Thus upstream speed is 55 km per hour

Downstream distance = 510 km

Downstream time = 6 hours

<h3><u>Find downstream speed:</u></h3>

$speed = \frac{510}{6}\\\\speed = 85$

Thus downstream speed is 85 km per hour

<em><u>If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then</u></em>

Speed downstream = u + v km/hr

Speed upstream = u - v km/hr

Therefore,

u + v = 85 ----- eqn 1

u - v = 55 ----- eqn 2

Solve both

Add them

u + v + u - v = 85 + 55

2u = 140

u = 70

<em><u>Substitute u = 70 in eqn 1</u></em>

70 + v = 85

v = 85 - 70

v = 15

Thus rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr

3 0

3 years ago