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riadik2000 [5.3K]
3 years ago
13

In the chemical reaction: 2 NaCl (s) + Pb(NO3)2 (aq) ---> 2 NaNO3 (aq) + PbCl2 (s), a student adds 2.5 grams of NaCl(s) to ex

cess lead (II) nitrate solution. What is the theoretical mass, in grams, of the precipitate (solid) formed
Chemistry
1 answer:
lakkis [162]3 years ago
4 0
The amount of the precipitate PbCl2 can be obtained using stoichiometry, assuming the reaction goes into completion given the excess amounts of the lead (II) nitrate solution. First, divide 2.5 g NaCl to its MW of 58.44 g/ mol to obtain the moles of NaCl involved in the reaction. Second, knowing that for every 2 moles of NaCl, there is 1 mole of PbCl2 produced, we divide the moles of NaCl obtained earlier by 2 to get the moles of PbCl2 produced. From the moles of PbCl2, we multiply it to its MW of 278.1 g/ mol. The amount of precipitate is then calculated to be 5.9484 g PbCl2. 
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yarga [219]

Given what we know, we can confirm that as with any experiment, the control variable will be the one that through each trial of the experiment, no matter how many times it is performed, stays constant.

<h3>What is a controlled variable?</h3>
  • A variable that remains constant through an experiment.
  • They are used to compare results to the normal condition.
  • They are also used to isolate the changes to one factor at a time and thus know its exact effects on the outcome.
  • This increases the accuracy of the data and the subsequent conclusion.

Therefore, we can confirm that if a variable stays constant through each phase and trial of an experiment, it is considered to be a controlled variable and is useful in order to increase the accuracy of the conclusion.

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7 0
3 years ago
How many moles of PC15 can be produced from 58.0 g of Cl₂ (and excess<br> P4)?
ludmilkaskok [199]

0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess

P4)

<h3>How to calculate moles?</h3>

The balanced chemical equation is

P_{4}  + 10Cl_{2}  = 4PCl_{5}

The mass of clorine is m(Cl_{2}) = 58.0 g

The amount of clorine is n(Cl_{2}) = m(Cl_{2})/M(Cl_{2}) = 58/70.906 = 0.817 mol

The stoichiometric reaction,shows that

10 moles of Cl_{2} yield 4 moles of PCl_{5};

0.817 of Cl_{2} yield x moles of PCl_{5}

n(PCl_{5}) = 4*0.817/10 = 0.3268 mol

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3 0
2 years ago
What is the percent by volume of ethanol (C2H60, or ethyl alcohol) in the final solution when 90 mL of ethanol is diluted to a v
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Answer:

16.0%.

Explanation:

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V % of ethanol = (volume of ethanol / volume of the solution) x 100.

volume of ethanol = 90.0 mL, volume of the solution = 550.0 mL.

∴ V % of ethanol = (90.0 mL / 550.0 mL) x 100 = 16.36% ≅ 16.0%.

8 0
3 years ago
How many single covalent bonds can halogens form?
Simora [160]
One single covalent bond, hope this helps!
4 0
3 years ago
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allochka39001 [22]
MgCl2 because it is the only option in which a metal appears with a nonmetal. In this case, the metal transfers electrons to the nonmental because the metal has a lower ionization energy.
7 0
4 years ago
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