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3 years ago

Which is the next logical step in balancing the given equation?

Chemistry

2 answers:

crimeas [40]3 years ago

5 0

Answer:

A. Place the coefficient 2 in front of oxygen and nitrogen dioxide.

Explanation:

Balancing equations is a consequence of the law

of conservation of mass, according to this law, the mass of the reactants must be equal to the mass of the products, this means that the quantity of the atoms found in the reactants must be equal to the quantity of the products In this case, for the equation to be balanced, a coefficient of 2 must be added to oxygen and nitrogen dioxide.

Leya [2.2K]3 years ago

3 0

To balance the given equation, we apply elemental balance and count each elements per side. There are 2 nitrogens in the left side so there should be 2 moles of NO2. Since there are already 4 moles of O in the right side, there should be 2 moles of O2. Hence answer is a. Place the coefficient 2 in front of oxygen and nitrogen dioxide.

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at atmoshperic pressure, a balloon contains 2.00L of nitrogen of gas. How would the volume change if the Kelvin temperature were

Nataly [62]

<u>Answer:</u> The percent change in volume will be 25 %

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=2L\\T_1=T_1\\V_2=?\\T_2=75\% \text{ of }T_1=0.75\times T_1$

Putting values in above equation, we get:

$\frac{2L}{T_1}=\frac{V_2}{0.75\times T_1}\\\\V_2=\frac{2\times 0.75\times T_1}{T_1}=1.5L$

Percent change of volume = $\frac{\text{Change in volume}}{\text{Initial volume}}\times 100$

Percent change of volume = $\frac{(2-1.5)}{2}\times 100=25\%$

Hence, the percent change in volume will be 25 %

5 0

3 years ago

In reaction a, each sodium atom gives one electron to a chlorine atom in reaction be an isotope of oxygen decays to form an isot

aalyn [17]

Answer:

Exthermal heat, i think

Explanation:

6 0

3 years ago

You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,

bonufazy [111]

Answer:

$\frac{[F^{-}]}{[HF]}$ is larger

Explanation:

$pK_{a}=-logK_{a}$ , where $K_{a}$ is the acid dissociation constant.

For a monoprotic acid e.g. HA, $K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}$ and $\frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}$

So, clearly, higher the $K_{a}$ value , lower will the the $pK_{a}$

In this mixture, at equilibrium, $[H^{+}]$ will be constant.

$K_{a}$ of HF is grater than $K_{a}$ of HCN

Hence, $(\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})$

So, $\frac{[F^{-}]}{[HF]}$ is larger

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3 years ago

Which of these are formed when

makvit [3.9K]

Option d lo siento si es incorrecto

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2 years ago

Write at least three characteristics of acids and three characteristics of bases. These characteristics should be what makes the

ki77a [65]

Characteristics of acid

-It tastes sour
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-It turns blue litmus paper red

Characteristics of base

-It tastes bitter
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3 years ago