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denis23 [38]
3 years ago
9

Need help with these questions

Mathematics
1 answer:
pochemuha3 years ago
7 0

29) Turns is the ratio of annual amount to average amount.

Cost turns = 57,982.85/15,545 ≈ 3.73

Sales turns = 130,935.60/35,388 ≈ 3.70

30) Consider January of the following year to be month 13.

7/16 to 13/14 is 6 months less 2 days. There are 31 days in July, August, October, and December, so 4 more days than 30 days per month. The total number of days is 6*30 -2 +4 = 182

31) I = Prt = $5380×0.118333×90/360 = $159.16

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Which graph represents 9(x - 5) = -15y
MAVERICK [17]

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(0,3) and (5,0)

Step-by-step explanation:

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What is 2 5/12 -(-2 1/6) Express the answer in simplest form.
VladimirAG [237]
Answer:
= 29/12 − -13/6

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3 0
3 years ago
1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
HELP QUICKLY PLSSS!!!!!!!!!!<br><br> Evaluate square root -75s where s = -3
lord [1]

Answer:

15

Step-by-step explanation:

-75 x-3 is 225

Square root of 225 is 15

3 0
3 years ago
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