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Elodia [21]
3 years ago
16

Harriet earns the same amount of money each day. Her gross pay at the end of 7 work days is 35h + 56 dollars. Which expression r

epresents her gross pay each day
Mathematics
2 answers:
scoray [572]3 years ago
8 0
<span>In the question "Harriet earns the same amount of money each day. Her gross pay at the end of 7 work days is 35h + 56 dollars. Which expression represents her gross pay each day" To obtain the expression that represents her gross pay each day, we divide the given expression by 7 to get (35h + 56) / 7 = 35h / 7 + 56 / 7 = 5h + 8 Therefore, the expression that represents her gross pay each day is 5h + 8.</span>
WARRIOR [948]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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5. Suppose that a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organ
mart [117]

Answer:

Probability that the sample proportion will be greater than 0.5 is 0.8133.

Step-by-step explanation:

We are given that the a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organization is about to take a simple random sample of voters and will use the sample proportion to estimate p.

Suppose that the polling organization takes a simple random sample of 500 voters.

<em>Let </em>\hat p<em> = sample proportion</em>

The z-score probability distribution for sample proportion is given by;

               Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

           p = population proportion = 48%

           n = sample of voters = 500

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.50) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < \frac{0.50-0.48}{\sqrt{\frac{0.50(1-0.50)}{500} } } ) = P(Z < 0.89) = 0.8133

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.89 in the z table which has an area of 0.8133.</em>

Therefore, probability that the sample proportion will be greater than 0.50 is 0.8133.

6 0
3 years ago
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