(1) 36 days is 8 half-life periods,
so 24mg becomes 24mg times (1/2)^8 = 24 mg/256 = 0.094 mg
(2) 9.6/1.2 = 8, which means three half-life periods went by.
At the end of 4.5 days, there were 4.8 mg
At the end of 9.0 days, there were 2.4 mg
At the end of 13.5 days, there were 1.2 mg
(3) The activity is proportional to the amount of radioactive material remaining,
so after two half-life periods, the activity should be 1/4 of what it originally was.
So the initial activity was probably 12.0 Ci
The correct answer you are looking for is napalm
Hope this helps!
Answer:
Answer 'A' is correct
Explanation:
For any reaction to occur, 4 events must occur simultaneously. These are...
1. reacting compounds must be at concentrations that allow them to find on another. Such is concentration dependent and is referred to as Kinetic Feasibility.
2. reacting compounds must collide in very specific orientations for bonding to occur. The reacting compounds have unique molecular geometries such that bonding only occurs if the compounds collide in a required orientation.
3. The reacting compounds must have a natural tendency to react and form chemical bonds.
4. The reacting system must be at sufficient temperature (which delivers sufficient energy (ΔEₐ) such that events 1, 2 and 3 have the highest probability of occurring simultaneously. This occurs at the activation energy point (k = A·e^(-ΔEₐ/RΔT) => lnΔk = lnA - ΔEₐ/RΔT) => The Arrhenius Equation of Kinetic Reactivity.