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topjm [15]
3 years ago
13

How many atoms of calcium, Ca would be equal to 5.472 X 104 moles Ca?

Chemistry
1 answer:
Montano1993 [528]3 years ago
5 0
Answer:
             3.29 × 10²⁸ Atoms

Solution:
              Moles and Number of atoms are related to each other as,

                           Moles  =  Number of Atoms / 6.022 × 10²³   ------- (1)

Data Given;
                  Moles  =  5.472 ×10⁴

                  Number of Atoms  =  ?

Solving eq. 1 for Number of Atoms,

                        Number of Atoms  =  Moles  × 6.022 × 10²³

Putting values,

Number of Atoms  =  5.472 ×10⁴ mol × 6.022 × 10²³ atoms.mol⁻¹

Number of Atoms  =  3.29 × 10²⁸ Atoms
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agasfer [191]

Answer:

Twice  as much.

Explanation:

That's because the freezing point depression depends on the total number of solute particles.

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0.01 mol of C₆H₁₂O₆ gives 0.01 mol of solute particles.

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1 mol of NaCl gives 0.01 mol of Na⁺(aq) and 0.01 mol of Cl⁻(aq).

That's 0.02 mol of particles, so the freezing point depression of 0.01 mol·L⁻¹ NaCl will be twice that of 0.01 mol·L⁻¹ C₆H₁₂O₆.

6 0
3 years ago
Which atom will gain electrons in the reaction, and how many.
Anna35 [415]

Answer:

Most atoms do not have eight electrons in their valence electron shell. Some atoms have only a few electrons in their outer shell, while some atoms lack only one or two electrons to have an octet. In cases where an atom has three or fewer valence electrons, the atom may lose those valence electrons quite easily until what remains is a lower shell that contains an octet. Atoms that lose electrons acquire a positive charge as a result because they are left with fewer negatively charged electrons to balance the positive charges of the protons in the nucleus. Positively charged ions are called cations. Most metals become cations when they make ionic compounds.

Explanation:

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3 years ago
What would be the major product obtained from hydroboration–oxidation of the following alkenes?
zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an <u>"anti-Markovnikov" reaction</u>. This means that the "OH" will be added at the <em>least substituted carbon of the double bond.</em>

In the case of <u>2-methyl-2-butene</u>, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore <u>the "OH" will be added to carbon three</u> producing <u>3-methylbutan-2-ol</u>.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore<u> the "OH" will be added to carbon 2</u> producing <u>2-methylcyclohexan-1-ol</u>.

See figure 1

I hope it helps!

8 0
3 years ago
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