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topjm [15]
3 years ago
13

How many atoms of calcium, Ca would be equal to 5.472 X 104 moles Ca?

Chemistry
1 answer:
Montano1993 [528]3 years ago
5 0
Answer:
             3.29 × 10²⁸ Atoms

Solution:
              Moles and Number of atoms are related to each other as,

                           Moles  =  Number of Atoms / 6.022 × 10²³   ------- (1)

Data Given;
                  Moles  =  5.472 ×10⁴

                  Number of Atoms  =  ?

Solving eq. 1 for Number of Atoms,

                        Number of Atoms  =  Moles  × 6.022 × 10²³

Putting values,

Number of Atoms  =  5.472 ×10⁴ mol × 6.022 × 10²³ atoms.mol⁻¹

Number of Atoms  =  3.29 × 10²⁸ Atoms
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How many moles are present in 54.8 mL of mercury if the density of mercury is 13.6 g/mL?​
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Answer:

3.72 mol Hg

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Density = Mass over Volume

Explanation:

<u>Step 1: Define</u>

D = 13.6 g/mL

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<u>Step 2: Identify Conversions</u>

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13.6 g/mL = x g / 54.8 mL

x = 745.28 g Hg

<u>Step 4: Convert</u>

<u />745.28 \ g \ Hg(\frac{1 \ mol \ Hg}{200.59 \ g \ Hg} ) = 3.71544 mol Hg

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.71544 mol Hg ≈ 3.72 mol Hg

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2. What ions are present in what ratio in a solution of aqueous calcium chloride?
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Answer:

\mathrm{Ca}^{2+} \text { and } \mathrm{Cl} \text { - ions are present in } 1: 2 \text { ratio in a solution of aqueous calcium chloride. }

Explanation:

Here in Calcium Chloride ionic bond is present in between calcium and chlorine atoms. As we know according to Octet rule calcium have two excess atoms and for matching nearest noble gas electronic configuration. It donate two electrons to gain more stability and form \mathrm{Ca}^{2+}, while chlorine is deficient from one electron to meet nearest noble gas electronic configuration therefore two chlorine atoms accept excess electron from calcium individually and form two\mathrm{Cl}^{-} ions.

\text { Equation is as follows: } \mathrm{Ca}^{2+}+2 \mathrm{Cl}^{-} \rightarrow \mathrm{CaCl}_{2}

Hence aqueous solution of calcium chloride breaks the ionic bond pairing in one \mathrm{Ca}^{2+}and two\mathrm{Cl}^{-}ions: \mathrm{CaCl}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O} \quad \mathrm{Ca}^{2+}(\mathrm{ag})+2 \mathrm{Cl}(\mathrm{ag})

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