Answer: 14.2 grams
Explanation:-
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
of particles.
To calculate the number of moles, we use the equation:
given mass of phosphorous (P) = 3.07 g
Molar mass of phosphorous (P) = 31 g/mol
Putting in the values we get:
given mass of oxygen
= 6.09 g
Molar mass of oxygen
= 32 g/mol
Putting in the values we get:
According to stoichiometry:
![4P+5O_2\rightarrow 2P_2O_5](https://tex.z-dn.net/?f=4P%2B5O_2%5Crightarrow%202P_2O_5)
4 moles of phosphorous combine with 5 moles of oxygen
Thus 0.1 moles of phosphorous combine with =
moles of oxygen
Thus phosphorous acts as limiting reagent as it limits the formation of product and oxygen is the excess reagent.
4 moles of phosphorous gives= 2 moles of ![P_2O_5](https://tex.z-dn.net/?f=P_2O_5)
Thus 0.1 moles of phosphorous gives =
moles of ![P_2O_5](https://tex.z-dn.net/?f=P_2O_5)
mass of ![P_2O_5=moles\times {\text {Molar mass}}=0.05\times 284=14.2g](https://tex.z-dn.net/?f=P_2O_5%3Dmoles%5Ctimes%20%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D0.05%5Ctimes%20284%3D14.2g)
Thus the theoretical yield of
is 14.2 grams.