Answer:
The order is: electron, carbon, water, glucose, glycogen.
Explanation:
The electron is a negatively charged subatomic particle and is therefore the smallest.
Carbon is a chemical element, which belongs to the group-14 of periodic table and has atomic number 6.
Water is a odorless, almost colorless and tasteless chemical compound which is necessary for all the known living form. The chemical formula is H2O and it is composed of 2 hydrogen atoms and one oxygen atom.
Glucose is a monosaccharide sugar and a type of simple carbohydrate. The chemical formula is C6H12O6 and is composed of 6 carbon atoms, 6 oxygen atoms and 12 hydrogen atoms.
Glycogen is a branched polysaccharide molecule, which is composed of multiple monomeric glucose units. Therefore, it is the largest.
<u>Therefore, the increasing order is: electron, carbon, water, glucose, glycogen.</u>
By adding together the number of protons and neutrons and multiplying by 1 amu, you can calculate the mass of the atom.
Answer:
10.9%.
Explanation:
The first thing to do in order to solve this question is to Determine the value for the volume of the the cube. This can be done by taking the cube root of the length of the cube;
The volume of the cube = (length of the cube)^3 = length × length × length = 1.72 × 1.72 × 1.72 =( 1.72)^3 = 5.09cm^3.
The next thing you do is to Determine the exponential density, the can be done by using the formula below;
The exponential density = mass/ volume = 55. 786/ 5.09 = 10.96 g/cm^3.
Therefore, the percent error = (true density of the cube - exponential density of the cube)÷ true density of the cube × 100.
Hence, the percent error = 12.30 - 10.96/12.30 × 100 = 10.9%.
Answer:
Formula: Na2S2O3
we get solubility.
Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .
Solution given:
mass of sodium thiosulphate [m1]=25.5g
mass of water [m2]=40g
at temperature [t]=25°C
we have
<u>solubility in g/dm^3</u> :
- =
- =63.75g /litre=63.75g/dm³
<u>solubility in g/dm^3 :63.75g/dm³</u>
<u>n</u><u>o</u><u>w</u>
solubility of the solute in mol/dm^3=:63.75g/dm³/178=0.4 mol/dm³
