Answer:
The name of the compound is:
4–bromo–5,5–dichloro–hex–3–ene–1–yne
Explanation:
To the above compound, we simply do the following:
1. Identify the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached.
4. Give the substituents the lowest possible count alphabetically.
5. Combine the above to obtain the name of the compound.
Now, we shall determine the name of the compound as follow:
1. The compound has carbon to carbon triple bond (C≡C) yne and carbon to carbon double bond (C=C) ene.
2. The longest continuous carbon chain is 6 i.e hexane.
3. The substituents group attached are:
i. Bromine (bromo), Br
ii. Chlorine (Chloro), Cl
4. In counting, ene comes before yne. But in this case, ene assumes same position from either side, So we shall consider counting from the side that gives yne the lowest count. Thus, ene is at carbon 3 and yne is at carbon 1. Therefore,
i. Bromo, Br is at carbon 4.
ii. Chloro, Cl appears twice and both are at carbon 5.
5. The name of the compound is:
4–bromo–5,5–dichloro–hex–3–ene–1–yne.
