Answer: Moles of solute particles are present in 272 mL solution of 0.242 M are 0.0658.
Explanation:
Molarity is defined as the number of moles of solute dissolved per Liter of the solution.
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of solution = 0.242 M
Volume of solution = 272 mL
Putting values in equation 1, we get:
Thus moles of solute particles are present in 272 mL solution of 0.242 M are 0.0658.
Answer:
In glucose there are 6 carbon atom, atomic weight carbon is 12, so the molar mass is 72 and the percentage composition of carbon in C6H12O6=(72180)×100%=40% percentage by the mass.
Molar mass ( CuSO₄) = 159.609 g/mol
159.609 g ----------------- 6.02 x 10²³ molecules
? g ------------------ 3.36 x 10²³ molecules
mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³
mass = 5.36 x 10²⁴ / 6.02 x 10²³
mass = 8.90 g
hope this helps!
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