Question

On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(1, 2). What is the length of Side RT of the polygon?

Answer 1

The distance between any two points can be found using the Pythagorean Theroem...

d^2=(x2-x1)^2+(y2-y1)^2  in this case

d^2=(2-2)^2+(1--6)^2

d^2=0+49

Since d>0 

d=7 units

Answer 2

Answer:

The length of Side RT of the polygon is $7\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$R(-6,2)\\T(1,2)$  

substitute the values

$d=\sqrt{(2-2)^{2}+(1+6)^{2}}$

$d=\sqrt{(0)^{2}+(7)^{2}}$

$dRT=7\ units$