Answer:
Second option - The bond is very polar
Explanation:
Electronegativity of an basically refers to the degree at which an electron is able to attract electrons to itself.
There are different types of bonds between atoms, depending on the electronegativity of the atoms.
When there is a large difference in electronegativity, it pretty much means that one atom would draw electrons more than the other. When this happens, the bond is said to be polar because there is uneven distribution of the charges.
The second option is the correct answer in thus question.
Answer:
Answer is C
Explanation:
All the variables can affect the results in an experiment
Answer:
The answer is B
Explanation:The answer is B because the color would be irreversible.
Answer:
CO(g) + H₂O(g) <=> CO₂(g) + H₂(g), (volume is decreased) .. No effect.
PCl₃(g) + Cl₂(g) <=> PCl₅(g)
, (volume is increased) .. Shift left.
CaCO₃(s) <=> CaO(s) + CO₂(g)
, (volume is increased) .. Shift right.
Explanation:
<em>Le Châtelier's principle</em><em> states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>
<em />
<em>CO(g) + H₂O(g) <=> CO₂(g) + H₂(g) (volume is decreased)</em>
- When volume is decreased, the pressure will increase:
- When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 2.0 moles of gases and the products side (right) has 2.0 moles of gases.
So, decreasing the volume will have no effect on the reaction.
<em>PCl₃(g) + Cl₂(g) <=> PCl₅(g)
, (volume is increased)</em>
- When volume is increased, the pressure will decrease:
- When there is an decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 2.0 moles of gases and the products side (right) has 1.0 mole of gases.
- So, decreasing the pressure will shift the reaction to the side with more moles of gas (left side).
so, increasing the volume will shift the reaction left.
<em>CaCO₃(s) <=> CaO(s) + CO₂(g)
, (volume is increased)</em>
- When volume is increased, the pressure will decrease:
- When there is an decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 0 moles of gases and the products side (right) has 1.0 mole of gases.
- So, decreasing the pressure will shift the reaction to the side with more moles of gas (right side).
so, increasing the volume will shift the reaction right.