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stepladder [879]
3 years ago
14

Print

Chemistry
1 answer:
Blizzard [7]3 years ago
3 0

Answer:

nitrogen 78% oxygen 21%   argon 0.9% carbon dioxide, nitrous oxide, methane, and ozone are trace gases that account for about a tenth of one percent of the atmosphere.

Explanation:

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Answer:

Enthalpy change is negative

Entropy change is Positive

Explanation:

4 0
3 years ago
Which is an example of a chemical reaction
valkas [14]

Answer:iron and oxygen combining to make rust. vinegar and baking soda combining to make sodium acetate, carbon dioxide and water

Explanation:

7 0
3 years ago
Is a compound a metal or non metal
VARVARA [1.3K]

Answer:

Compounds between Nonmetals and Nonmetals

Compounds that consist of a nonmetal bonded to a nonmetal are commonly known as Molecular Compounds, where the element with the positive oxidation state is written first. In many cases, nonmetals form more than one binary compound, so prefixes are used to distinguish them.

3 0
3 years ago
Does water and oil mix through,PLease help<br><br><br> I need the answer!!!!!!!!!!!!!!!!!!!!!!
Pani-rosa [81]
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Hope this helps!
6 0
3 years ago
Aluminum nitrate reacts with sodium hydroxide to form a precipitate of aluminum hydroxide. What mass of aluminum hydroxide will
lora16 [44]

Answer:

The mass of aluminum hydroxide that will precipitate when 35.5 mL of 0.145 mol/L aqueous aluminum nitrate is mixed with 44.2 mL of 0.215 mol/L aqueous sodium hydroxide is approximately 0.247 grams

Explanation:

The given parameters are;

The volume of 0.145 mol/L aqueous aluminum nitrate in the reaction = 35.5 mL

The volume of 0.215 mol/L aqueous sodium hydroxide in the reaction = 44.2 mL

The balanced chemical equation for the reaction is given as follows;

Al(NO₃)₃ (aq) + 3NaOH (aq) → Al(OH)₃ (s) + 3NaNO₃ (aq)

Therefore;

1 mole of Al(NO₃)₃, reacts with 3 moles of NaOH to form 1 mole Al(OH)₃, and 3 moles of NaNO₃

The number of moles of aqueous aluminum nitrate in the reaction = 35.5/1000 L × 0.145 mol/L = 0.0051475 moles

The number of moles of aqueous sodium hydroxide in the reaction = 44.2/1000 L × 0.215 mol/L = 0.009503 moles

Therefore, 0.009503 moles NaOH will react with 0.009503/3 moles Al(NO₃)₃ to form 0.009503/3 moles of aluminum hydroxide precipitate

The molar mass of aluminum hydroxide = 78 g/mol

Therefore, 0.009503/3 moles of aluminum hydroxide weighs 78 × 0.009503/3 = 0.247078 grams

The mass of aluminum hydroxide that will precipitate out ≈ 0.247 grams.

7 0
3 years ago
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