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A molecular formula represents the exact number of atoms present for each element in the compound.
For carbon atom: =
( as molar mass of carbon is 12 g/mol)
Now, 6 carbon atoms are present and rest are hydrogen atoms i.e. 6
Thus, formula becomes (
Now, check for unsaturation:
Degree of unsaturation =
Substitute the value of x and y,
Degree of unsaturation =
=
= implies one ring and three double bonds.
Thus, formula comes out to be i.e. benzene ring.
<u>Answer:</u> The moles of bromine gas at equilibrium is 0.324 moles.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
.......(1)
Calculating the initial moles of hydrogen and bromine gas:
- <u>For hydrogen gas:</u>
Moles of hydrogen gas = 0.682 mol
Volume of solution = 2.00 L
Putting values in equation 1, we get:
- <u>For bromine gas:</u>
Moles of bromine gas = 0.440 mol
Volume of solution = 2.00 L
Putting values in equation 1, we get:
Now, calculating the molarity of hydrogen gas at equilibrium by using equation 1:
Equilibrium moles of hydrogen gas = 0.566 mol
Volume of solution = 2.00 L
Putting values in equation 1, we get:
Change in concentration of hydrogen gas = 0.341 - 0.283 = 0.058 M
This change will be same for bromine gas.
Equilibrium concentration of bromine gas =
Now, calculating the moles of bromine gas at equilibrium by using equation 1:
Molarity of bromine gas = 0.162 M
Volume of solution = 2.00 L
Putting values in equation 1, we get:
Hence, the moles of bromine gas at equilibrium is 0.324 moles.