Answer:
The concentration is 0.111 M.
Explanation:
Use dimensional analysis to solve the problem. Since both HCl and NaOH are strong, the dissociate completely in solution.
For this neutralization, the reaction is HCl + NaOH = NaCl + HOH
18.5 mL x 
x 
x 
= 0.002775 moles HCl
Molarity = moles/ Liters
Molarity of HCl = 0.002775 moles HCl / 0.025 L = 0.111 M
Farm water runoff, which causes nitrogen rich fertilizer to be washed into the body of water. The nitrogen feeds the algae bloom.. Hope this helps
The answer is either 38 g or 40.g KCLO3. If it 95% instead of 895%.
Hrxn = Q reaction / mol of reaction
mol of reaction = M * V = 10 * 1 = 10 mmol = 0.01 mol
Q water = m * C * (Tf - Ti)
= (10 + 10) (4.184) (26-20) = 502.08 J
Q reaction = - Q water = -502.08 J
Hrxn = -502.08 / (0.01) = - 50208 J = - 50.21 kJ/mol
