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Bingel [31]
2 years ago
11

The concentration of hydrogen peroxide (H2O2) can be determined by titrating it with an acidified MnO4− solution. The following

is an unbalanced equation.
MnO4− (aq) + H2O2 (aq) → O2 (g) + Mn2+ (aq)

(a) Balance the above redox reaction.
(b) Determine the concentration of H2O2 solution in molarity if 10.00 mL of this solution requires 20.00 mL of 1.5 M MnO4− for a complete reaction.
Chemistry
1 answer:
Vaselesa [24]2 years ago
5 0

Answer:

A) {MnO_4}^- + 3 H^+ + \frac{5}{2} H_2O_2 \rightarrow Mn^{2+} + 4 H_2O + \frac{5}{2} O_2

B) 7.5 molar

Explanation:

A) <u>Reduction</u>

{MnO_4}^- + 8 H^+ + 5e^- \rightarrow Mn^{2+} + 4 H_2O

<u>Oxidation</u>

H_2O_2 \rightarrow O_2 + 2 H^+ + 2e^-

Multiplying the oxidation reaction by 5/2 and adding it to the reduction equation:

{MnO_4}^- + 8 H^+ + 5e^- \rightarrow Mn^{2+} + 4 H_2O

+

\frac{5}{2} H_2O_2 \rightarrow \frac{5}{2} O_2 + 5 H^+ + 5e^-

-----------------------------------------------------------------------------------------------------

{MnO_4}^- + 3 H^+ + \frac{5}{2} H_2O_2 \rightarrow Mn^{2+} + 4 H_2O + \frac{5}{2} O_2

B) 10 ml = 0.01 L

20 ml = 0.02 L

mol of MnO4− = molarity*volume = 1.5*0.02 = 0.03

1 mol of MnO4− reacts with 5/2 mol of H2O2, then:

mol of H2O2 = 0.03*5/2 = 0.075

molarity = mol/volume = 0.075/0.01 = 7.5 molar

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Answer:

M = 0.23 M

Explanation:

Given data:

Molarity of solution = ?

Mass of NH₄Br = 4.50 g

Volume of solution = 213 mL (213 mL× 1L /1000 mL = 0.213 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of NH₄Br:

Number of moles = mass/molar mass

Number of moles = 4.50 g / 97.94 g/mol

Number of moles = 0.05 mol

Molarity:

M = 0.05 mol/ 0.213 L

M = 0.23 M

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The density of a metal is 11.4 g/cm3. How much volume (in cm3) would a sample of 30.5 g have?
julia-pushkina [17]

<u>The Concept:</u>

We are given the density of a sample of the metal = 11.4 grams / cm³

and we need to find the volume occupied by a sample of 30.5 grams

For this solution, we will use dimensional analysis

from the given information, we can also say that the density of the metal is:

1 cm³ / 11.4 grams

If we multiply this value by 30.5 grams, the 'grams' in the numerator and the denominator will cancel out and we will be left with the volume occupied by 30.5 grams of the metal

<u>Solving for the volume:</u>

\frac{ 1 cm^{3} }{11.4 grams}  X  30.5 grams  = (30.5 / 11.4) cm³

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A student wonders whether a piece of jewelry is made of pure silver. She determines that its mass is 3.25 g. Then she drops it i
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Answer:

The jewelry is 2896.54_Kg/m^3 less dense than pure silver

Explanation:

Density of jewellery = (mass of jewellery) ÷ (volume of jewellery)

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The density of silver is 10490_Kg/m^3 which is (10490 - 7583.46) 2896.54_Kg/m^3 more dense than the jewellery

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The weight of Silver per cubic centimeter is 10.49 grams or the weight of silver per cubic meter is 10490 kilograms, that is the density of silver is 10490 kg/m³; at 20°C (68°F or 293.15K) at a pressure of one atmospheres.

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How many monochlorination products can be formed (constitutional isomers only) from the reaction of (CH3)2CHCH2CH3 with Cl2 and
faltersainse [42]

Answer:

4 monochlorination products can be formed.

Explanation:

Constitutional isomers : These are those compounds with same molecular formula but different atomic arrangement.For example: butane and 2-methly-propane.

On monochlorination of 2 methyl-butane  we will have four possibilities of product which will be constitutional isomers of each other:

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