All categories

3 years ago

I need a science fair topic and the science fair is in 3 days

Chemistry

2 answers:

vitfil [10]3 years ago

8 0

Electric circuit and electricity conductors are relatively simple to explain

alisha [4.7K]3 years ago

3 0

Make it about volcanos sis

You might be interested in

How important is economic in your everyday life

docker41 [41]

Answer:

it is mega important.

Explanation:

3 0

3 years ago

The elements in Groups 1 and 2 get more reactive as you go down the group.

deff fn [24]

Answer:

Sodium and Magnesium

Explanation:

The elements in Groups 1 and 2 get more reactive as you go down the group.

This means that Sodium is more reactive than lithium and Magnesium is more reactive than beryllium.

On the periodic table, as you go down the group, the reactivity of an element increases. Especially with metals in group 1 and 2. Now Lithium is a metal of group 1, followed by Sodium, while Beryllium is a metal in group 2, followed by magnesium. That's how I picked the answers

4 0

3 years ago

A gas occupies 1200 litres at 2 atm pressure. To what pressure must it be compressed to occupy 60 litres at the same temperature

MArishka [77]

P2 = 40 atm

Explanation:

Given:

P1 = 2 atm

V1 = 1200 L

V2 = 60 L

P2 = ?

Using Boyle's law and solving for P2,

P1V1 = P2V2

P2 = (V1/V2)P1

= (1200 L/60 L)(2 atm)

= 40 atm

8 0

3 years ago

15.0 mL of 0.050 M Ba(NO3)2 M and 100.0 mL of 0.10 M KIO3 are added together in a 250 mL erlenmeyer flask. In this problem, igno

timama [110]

Answer:

Yes, precipitation of barium iodate will occur.

Explanation:

Molarity of barium nitrate solution = 0.050 M

Volume of barium nitrate solution =15.0 mL = 0.0150 L

1 mL = 0.001 L

Moles of barium nitrate = n

$n=0.050 M\times 0.0150L=0.00075 mol$

$Ba(NO_3)_2(aq)\rightarrow Ba^{2+}(aq)+2NO_3^{-}(aq)$

Moles of barium ions: $1\times 0.00075 mol=0.00075 mol$

Molarity of potassium iodate solution = 0.10 M

Volume of potassium iodate solution =100.0 mL = 0.1000 L

1 mL = 0.001 L

Moles of potassium iodate = n'

$n'=0.10 M\times 0.1000 L=0.01 mol$

$KIO_3(aq)\rightarrow K^{+}(aq)+IO_3^{-}(aq)$

Moles of iodate ions = $1\times 0.01 mol=0.01 mol$

After mixing of both solution in 250 mL in erlenmeyer flask

Volume of the final solution = 250 mL = 0.250 L

Concentration of barium ions in 250 mL solution :

$[Ba^{2+}]=\frac{0.00075 mol}{0.250 L}=0.003 M$

Concentration of iodate ions:

$[IO_3^{-}]=\frac{0.01 mol}{0.250 L}=0.04 M$

Solubility product of barium iodate, $K_{sp}=4.01\times 10^{-9}$

Ionic product of the barium iodate in solution : $K_i$

$Ba(IO_3)_2\rightleftahrpoons Ba^{2+}+2IO_3^{-}$

$K_i=[Ba^{2+}][IO_2^{-}]^2$

$K_i=0.003 M\times (0.04 M)^2=4.8\times 10^{-6}$

$K_{sp}$ ( precipitation)

As we can see, the ionic product of the barium iodate is greater than the solubility product of the barium iodate precipitation of barium iodiate will occur in 250 mL of final solution.

5 0

4 years ago

Total these measurements. Your answer should indicate the proper accuracy.

Gnesinka [82]

Answer:

Total of all numbers added with the correct rounding and number of significant figures

Explanation:

1. Add up all the numbers

8.32+8.00+8.30+8.3

2. Determine how many significant figures should be in your final answer. When it comes to addition, it will be the fewest number of decimal places. since 8.3 has one decimal place, your final answer should only have one decimal place.

3. Round your final answer to the nearest tenths

8 0

3 years ago