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Mice21 [21]
2 years ago
6

R'=2 Ohm R"=1,5 Ohm R"'=2 Ohm​

Physics
1 answer:
Andrew [12]2 years ago
5 0

Answer:

2.5 ohm

Explanation:

R' and R''' are parallel

So,

1/R1= 1/R' + 1/R'''

1/R1 = 1/2 + 1/2

1/R1 = 1

so,

R1= 1 ohm

Now R1 and R'' are in series

so,

R= R1 + R''

R= 1 + 1.5

R= 2.5 ohm

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Why does a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude
inna [77]

Answer:

According to your question although I think an object undergoing uniform circular motion is moving with a constant speed. Nevertheless, it is accelerating due to its change in direction. The direction of the acceleration is inwards,therefore a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude.

3 0
3 years ago
A pendulum is observed to complete 20 full cycles in 60 seconds. Determine the period and the frequency of the pendulum.
Delvig [45]

i hope i have been useful buddy.

good luck ♥️♥️

5 0
3 years ago
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During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.22 s, how high does it rise? The accel
BigorU [14]

Answer:

47.4 m

Explanation:

When an object is thrown upward, it rises up, it reaches its maximum height, and then it goes down. The time at which it reaches its maximum height is half the total time of flight.

In this case, the time of flight is 6.22 s, so the time the ball takes to reach the maximum height is

t=\frac{6.22}{2}=3.11 s

Now we consider only the downward motion of the ball: it is a free fall motion, so we can find the vertical displacement by using the suvat equation

s=ut+\frac{1}{2}gt^2

where

s is the vertical displacement

u = 0 is the initial velocity

t = 3.11 s is the time

g=9.8 m/s^2 is the acceleration of gravity (taking downward as positive direction)

Solving the  formula, we find

s=\frac{1}{2}(9.8)(3.11)^2=47.4 m

7 0
3 years ago
Using -10 m/s2 for acceleration due to gravity, what would be the total displacement of the object if it took 8 seconds before h
ASHA 777 [7]
If it starts from 0m/s...
s=?
u=0
a=-10
t=8
s=ut +1/2at^2
so s=(0×8)+ (0.5×-10×64)
s=0+(32×-10)
s=32×-10
s=-320metres
6 0
3 years ago
I need help with this question ASAP I am on a timer
Tom [10]
First box and third box !
4 0
2 years ago
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