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Alona [7]
3 years ago
15

A sound wave has a speed of 345 m/s and a wavelength of 500 meters. Is it infrasonic, sonic, or ultrasonic

Physics
1 answer:
exis [7]3 years ago
4 0

Answer:

Infrasonic.

Explanation:

Given the following data;

Speed = 345 m/s

Wavelength = 500 meters

To find the frequency of the sound wave;

Speed = wavelength * frequency

Frequency = speed/wavelength

Frequency = 345/500

Frequency = 0.69 Hz

Therefore, the sound wave is infrasonic.

Note: Frequency of infrasonic sound = below 20 Hertz.

Frequency of sonic sound = 20 Hz to 20,000 Hertz.

Frequency of ultrasonic sound = above 20,000 Hertz.

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ASAP
iris [78.8K]

Answer:

A) Energy is dissipated into heat and sound energy due to Friction

B) The energy goes into heat and sound energy due to friction again, otherwise the cart would accelerate due to an unbalanced force. Therefore, we know there's friction, and the friction causes energy loss.

5 0
3 years ago
A crane lifts a load of 15000N to a height 40m in 50 seconds. Calculate the power of the crane​
Nataly [62]

Answer:

P = 12000 W

Explanation:

General data:

  • F = 15000 N
  • d = 40 m
  • t = 50 s
  • P = ?

Work is force times unit of distance. So in order to calculate the power we must first calculate the work.

Formula:

  • \boxed{\bold{W=\frac{F}{d}}}

Replace and solve

  • \boxed{\bold{W=\frac{15000\ N}{40\ m}}}
  • \boxed{\bold{W=600000\ J}}

once the work is found, we proceed to find the power according to the formula:

  • \boxed{\bold{P=\frac{W}{t}}}
  • \boxed{\bold{P=\frac{600000\ J}{50\ s}}}
  • \boxed{\boxed{\bold{P=12000\ W}}}

The power of the crane is <u>12000 Watts.</u>

Greetings.

6 0
3 years ago
Same diagram... Which location shows SUMMER in the SOUTHERN hemisphere? *
LiRa [457]
Location 1 is correct
7 0
3 years ago
Read 2 more answers
A car is traveling at 15m/s on a horizontal road. the brakes are applied and the car skids to a stop in 4.0s . the coefficient o
iren2701 [21]

Answer:

the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

Explanation:

Given that;

final velocity v = 0

initial velocity u = 15m/s

time taken t = 4 s

acceleration  a = ?

from the equation of motion        

v   =   u   +   at

we substitute

0 = 15 + a × 4

acceleration a = -15/4 =  - 3.75 m/s²    

the negative sign tells us that its a  deacceleration so the sign can be ignored.

Deacceleration due to friction a = μ × g

we substitute

3.75 = μ × 9.8    

μ = 3.75 / 9.8 = 0.3826 ≈ 0.38

Therefore the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

8 0
3 years ago
1. The efficiency of a Carnot engine is e=1-Tc/TH, where Tc is a temperature of the cold reservoir and TH is a temperature of th
Shalnov [3]

Answer:

Tc=0

Explanation:

The condition to have 100% efficiency is e=1-Tc/TH=1, so Tc/TH=0, As TH is different of zero we can conclude

Tc=0 Kelvins.

7 0
3 years ago
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