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Alona [7]
2 years ago
15

A sound wave has a speed of 345 m/s and a wavelength of 500 meters. Is it infrasonic, sonic, or ultrasonic

Physics
1 answer:
exis [7]2 years ago
4 0

Answer:

Infrasonic.

Explanation:

Given the following data;

Speed = 345 m/s

Wavelength = 500 meters

To find the frequency of the sound wave;

Speed = wavelength * frequency

Frequency = speed/wavelength

Frequency = 345/500

Frequency = 0.69 Hz

Therefore, the sound wave is infrasonic.

Note: Frequency of infrasonic sound = below 20 Hertz.

Frequency of sonic sound = 20 Hz to 20,000 Hertz.

Frequency of ultrasonic sound = above 20,000 Hertz.

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Answer:

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Explanation:

6 0
3 years ago
Describe what happens when your circuit is completed. Tap on one of the wires with your mouse. Describe what happens. Explain yo
klemol [59]

Answer: when a circuit is completed (it allows the flow of electrons which causes the light bulb to produce light).

Explanation:

A circuit is described as an electrical setup that is consists of a light bulb, a switch, a wire, a battery which is arranged to allow the flow of electric current. The major components of the electrical circuit includes:

--> The BATTERY which is the source of voltage to the circuit,

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6 0
2 years ago
A radioactive isotope of the element potassium decays to produce argon. If the ratio of argon to potassium is found to be 31:1,
iris [78.8K]

Answer:

Explanation:

Argon to potassium ratio after 1 half life = 1:1

After 2 half lives = 75/25= 3:1

After 3 half lives = 87.5/12.5= 7:1

After 4 half lives = 93.75/6.25 = 15:1

After 5 half lives = 96.875/3.125 = 31/1

8 0
3 years ago
an object moving at 10. km/hr has a kinetic energy of 10. J. what is the kinetic energy of the same object if it is moving at 20
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KE = (1/2)mv^2

solve for mass m
10 = (1/2)m(10)^2
10 = (1/2)m(100)
10= 50m
10/50 = m
1/5 = m

at 20 km/hr

KE = (1/2)(1/5)(20)^2
KE = (1/10)(400)
KE = 40 J
5 0
3 years ago
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lozanna [386]

AnswerAmontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas (Figure 1).:

Explanation:

5 0
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