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kenny6666 [7]
2 years ago
12

A sort of "projectile launcher" is shown below. A large current moves in a closed loop composed of fixed rails, a power supply,

and a very light, almost frictionless bar touching the rails. A magnetic field is perpendicular to the plane of the circuit. The bar has a length of 20 cm, a mass of 1.2 g, and is placed in a field of 1.7 T.
a) What constant current flow is needed in order for it to accelerate to 33 m/s in a distance of 1.0 m?

b) In what direction must the field point?

PLEASE ANSWER OR ATLEAST TRY!!! Please and thank you.
Physics
1 answer:
Zarrin [17]2 years ago
3 0

Answer:

wallah i don't understand anything with my stoopid brain

Explanation:

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The flaming gorge bridge, in wyoming rises above a dry gulch. If you throw a rock straight out from the bridge, horizontally, an
Novosadov [1.4K]

Answer:

12.495m/s

Explanation:

Horizontal displacement is the range of the projectile motion.

The range is expressed as;

R = 2U/g

U is the speed at which the rock is thrown (initial speed)

g is the acceleration due to gravity.

Given

R = 255cm = 2.55m

g = 9.8m/s²

Required

Speed U

Substitute the given parameters into the formula as shown;

2.55 = 2U/9.8

Cross multiply

2U = 2.55×9.8

2U = 24.99

U = 24.99/2

U = 12.495m/s

Hence the speed that you thew the rock is 12.495m/s

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2 years ago
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saul85 [17]
No they don’t lol I hate school
6 0
3 years ago
The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is J. (Report the answer to two significant figu
abruzzese [7]

Answer:

\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}

Given:

Mass (m) = 6.8 kg

Speed (v) = 5.0 m/s

To Find:

Kinetic energy (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 6.8 \times  {5}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 3.4 \times 25

\sf \implies KE =3.4 \times 25

\sf \implies KE = 85 \: J

8 0
3 years ago
Read 2 more answers
Please answer the question below
scoundrel [369]
The correct answer is B.
In a velocity vs time graph, a line going up means an increase in velocity, or speed, which correlates to positive acceleration. Negative acceleration means slowing down.
6 0
3 years ago
PLEASE HELP!!
dedylja [7]
Pretty sure it’s A. Hope this helps.
4 0
3 years ago
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