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2 years ago

What is the advantage in solving motion problems using energy conservation principles instead of free body diagrams

Physics

1 answer:

riadik2000 [5.3K]2 years ago

5 0

Answer:

However, the disadvantages are:

1. Many atimes for some motion prolems, free-body diagrams has to be drawn many times so to have enough equations to solve for the unknowns. This is not the same with energy conservation principles.

2. In situations where we need to find the internal forces acting on an object, we can't truly solve such problems using free-body diagram as it captures external forces. This is not the same with energy conservation principles.

Explanation:

Often times the ideal method to use in solving motion problem related questions are mostly debated.

Energy conservation principles applies to isolated systems are useful when object changes their positions in moving upward or downward converts its potential energy due to gravity for kinetic energy, or the other way round. When energy in a system or motion remains constant that is energy is neither created nor destroyed, it can therefore be easier to calculate other unknown paramters like in the motion problem velocity, distance bearing it in mind that energy can only change from one type to another.

On the other hand, free body diagram which is a visual representation of all the forces acting on an object including their directions has so many advantages in solving motion related problems which include finding relationship between force and motion in identifying the force acting on a body.

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Using no more than 3 sentences, explain how a motor and generator are related.

kogti [31]

The Electric Motor and Generator are differentiated on various factors like the main principle of working or function of the motor and generator. Consumption or production of electricity, its driven element, the existence of the current in the winding. Fleming’s rule followed by the motor and generator.

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2 years ago

A steel wire of length 4.7 m and cross section 3 x 103 m2 stretches by the same amount as a copper wire of length 3.5 m and cros

EleoNora [17]

Answer:

The ratio of the young's modulus of steel and copper is $1.79\times10^{-2}$

(c) is correct option.

Explanation:

Given that,

Length of steel wire = 4.7 m

Cross section $A = 3\times10^{-3}\ m^2$

Length of copper wire = 3.5 m

Cross section $A = 4\times10^{-5}\ m^2$

We need to calculate the ratio of young's modulus of steel and copper

Using formula of young's modulus for steel wire

$Y=\dfrac{\dfrac{F}{A}}{\dfrac{\Delta l}{l}}$

$Y_{s}=\dfrac{Fl_{s}}{A_{s}\Delta l}$ ....(I)

The young's modulus for copper wire

$Y_{c}=\dfrac{Fl_{c}}{A_{c}\Delta l}$ ....(II)

From equation (I) and (II)

The ratio of the young's modulus of steel and copper

$\dfrac{Y_{s}}{Y_{c}}=\dfrac{\dfrac{Fl_{s}}{A_{s}\Delta l}}{\dfrac{Fl_{c}}{A_{c}\Delta l}}$

$\dfrac{Y_{s}}{Y_{c}}=\dfrac{A_{c}\times l_{s}}{A_{s}\times l_{c}}$

$\dfrac{Y_{s}}{Y_{c}}=\dfrac{4\times10^{-5}\times4.7}{3\times10^{-3}\times3.5}$

$\dfrac{Y_{s}}{Y_{c}}=1.79\times10^{-2}$

Hence, The ratio of the young's modulus of steel and copper is $1.79\times10^{-2}$

5 0

3 years ago

What are the function of mercury barometer

Orlov [11]

Answer:

A mercury barometer is an instrument used to measure atmospheric pressure in a certain location and has a vertical glass tube closed at the top sitting in an open mercury-filled basin at the bottom. Mercury in the tube adjusts until the weight of it balances the atmospheric force exerted on the reservoir.

Explanation:

3 0

2 years ago

Read 2 more answers

Transverse thrusters are used to make large ships fully maneuverable at low speeds without tugboat assistance. A transverse thru

suter [353]

Answer:

Thrust developed = 212.3373 kN

Explanation:

Assuming the ship is stationary

Determine the Thrust developed

power supplied to the propeller ( Punit ) = 1900 KW

Duct distance ( diameter ; D ) = 2.6 m

first step : calculate the area of the duct

A = π/4 * D^2

= π/4 * ( 2.6)^2 = 5.3092 m^2

next : calculate the velocity of propeller

Punit = (A*v*β ) / 2 * V^2 ( assuming β = 999 kg/m^3 ) also given V1 = 0

∴V^3 = Punit * 2 / A*β

= ( 1900 * 10^3 * 2 ) / ( 5.3092 * 999 )

hence V2 = 8.9480 m/s

Finally determine the thrust developed

F = Punit / V2

= (1900 * 10^3) / ( 8.9480)

= 212.3373 kN

8 0

3 years ago

Triton is a moon of Neptune. It has a

Alik [6]

Answer:

840.96 mi

Explanation:

6 0

2 years ago