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GuDViN [60]
3 years ago
8

Describe the relationship between the substrate and the product

Chemistry
1 answer:
il63 [147K]3 years ago
8 0

A simple chemical reaction with a single substrate shows a linear relationship between the rate of formation of product and the concentration of substrate, as shown below: ... The relationship between rate of reaction and concentration of substrate depends on the affinity of the enzyme for its substrate.

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In a different experiment, the student uses a calorimeter which is perfectly insulated. She fills the calorimeter with 100.0 g o
alexdok [17]

Answer:

Explanation:

Mg + 2HCl = Mg Cl₂ + H₂

.594 g = .594 / 24.3

= .02444 mole

Heat evolved = msΔ T , m is mass of water ( solvant ) , s is specific heat of water , Δ T is rise in temperature

= 100 x 4.2 x ( 41.83 - 25 )

= 7068.6 J

.02444 mole  of Mg evolves 7068.6 J of heat

1 mole of Mg evolves 7068.6 /.02444 J

= 289222.6 J

= 289 kJ .

Molar heat enthalpy = 289 kJ .

8 0
3 years ago
POINTS!!!!
Setler79 [48]
C) 3 Moles
This is because of the molecular structure shown in the image

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3 years ago
Which of the following would be the best representation of input energy and then
Rom4ik [11]
A is the correct answer
4 0
3 years ago
Calculate the electrical energy per gram of anode material for the following reaction at 298 K:
solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, <em>n</em>, equals 0.144 moles for each gram of the anode.

Let w_\text{max} represents the electrical energy produced.

w_\text{max} = n \cdot F \cdot E_\text{cell}, where

  • <em>n</em> is the <em>number of moles</em> electrons transferred,
  • <em>F</em> is the Faraday's constant,
  • <em>E</em>_\text{cell} is the cell potential,

<em>n </em>= 0.144 mol, as shown above, and

<em>F </em>= 96.486 kJ / (\text{V} \cdot \text{mol} \; \text{e}^{-}).

Therefore,

w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}.

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3 years ago
What is the electron configuration for Bromine? It has 27 electrons. I think the electron configuration for Bromine is : I'm sor
vfiekz [6]
The electron configuration for cobalt is:
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