For moles to grams would be the mole which is 7.9*10^-1 times the molar mass of argon
Answer:
a0=2
a1=3
a2=2
a3=4
Explanation:
The balanced equation for the complete combustion of methane is:
2CH₃OH₍l₎ + 3O₂₍g₎ → 2CO₂ + 4H₂O₍l₎
This way, there is an equal number of atoms of each kind on both reactants side and the products side.
Therefore the coefficients represented by the unknowns are:
a0=2
a1=3
a2=2
a3=4
The above is the equation for the complete combustion of methanol.
Answer:
Hi. I'll explain
Explanation:
If you round it it will be 251
D is the answer (251)
Answer:
a. See figure 1
b. See figure 2
c. Three cycles
d. Four Acetyl-CoAs
Explanation:
<u>a. Draw the condensed structural formula for the activated form of caprylic acid</u>
<u />
For the activation of the fatty acid, an ATP molecule is needed to bind AMP in the acid group and then an Acetyl-CoA molecule to generate the <u>activated fatty acid</u>. (See figure 1)
<u>b. Indicate the α- & β-carbon atoms in caprylic acid</u>
<u />
By definition, the alpha and beta carbons are the carbons that are in positions 2 and 3 respectively to the main carbon. In this case, the main carbon is the carbon from the acid group, therefore the <u>alpha carbon</u> will be carbon 2 (red arrow) and the <u>beta carbon</u> will be carbon 3 (blue arrow). (See figure 2).
<u>c. State the number of β-oxidation cycles for the complete oxidation of caprylic acid.</u>
<u />
To calculate the cycles we have to use the equation:
<u />
, where n is the amount of carbons, in this case, we have 8 carbons, so:
<u>
</u>
<u>We will have 3 cycles</u>. (See figure 3)
<u>d. State the number of acetyl-CoAs from the complete oxidation of caprylic acid</u>
In the β-oxidation metabolic cycle, we have a relationship between Acetyl-CoA produced and the number of carbons:
if n=8 we will have:
<u>We will have 4 Acetyl-CoAs</u>.
I hope it helps!
I'm assuming it would be ocean warming?
What are the options given?