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Monica [59]
3 years ago
7

How many electrons are in the second ring of sodium​

Chemistry
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

there are eight electrons

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Calculate the theoretical percentage of water for the following hydrates.
Svetradugi [14.3K]

Answer:

(a) \% H_2O=10.65\%

(b) \% H_2O=32.2

Explanation:

Hello.

For this questions we must consider the ratio of the molar mass of water to  hydrated compound molar mass as shown below:

(a) In this case, we can consider that inside the manganese (II) sulfate monohydrate, whose molar mass is 169.02 g/mol, there is one water molecule that has a molar mass of 18 g/mol, for which the theoretical percentage of water is:

\% H_2O=\frac{18g/mol}{169.0g/mol} *100\%\\\\\% H_2O=10.65\%

(b) In this case, we can consider that inside the manganese (II) sulfate tetrahydrate, whose molar mass is 223.1 g/mol, there are four water molecules that have a molar mass of 4*18 g/mol, for which the theoretical percentage of water is:

\% H_2O=\frac{4*18g/mol}{223.1g/mol} *100\%\\\\\% H_2O=32.27\%

Best regards.

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