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3 years ago

Snail 3, trying to keep up with Snail 2, managed to get to

Physics

1 answer:

Kipish [7]3 years ago

6 0

Answer:

Acceleration is the change in velocity over the change in time = Δv/Δt. To do these problems, you need to find out how much the speed changed and over what period of time it changed.

Snail 1 changes from 4 cm/min to 7 cm/min in 3 minutes. Subtract the starting velocity (4 cm/min) from the ending velocity (7 cm/min) then divide by the time (3 min):

Snail 1 = (7 cm/min. - 4 cm/min)/(3 minutes) = ? (remember to put down the units)

Snail 2 changed from 7 cm/min. down to 1 cm/min. in 3 minutes

Snail 2 = (1 cm/min. - 7 cm/min.)/(3 min.) = ? (note that the acceleration is negative when you slow down)

I hope this helps you

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A friend tells you that a rowboat is propelled forward by the force of its oars against the water. First explain whether the sta

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It is correct, the action is paddling, where you move the water backwards, and the reaction is the boat moving forwards.

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3 years ago

Explain how forces of attraction and repulsion exist within an atom

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Answer:

Oppositely charged particles attract each other, while like particles repel one another. Electrons are kept in the orbit around the nucleus by the electromagnetic force, because the nucleus in the center of the atom is positively charged and attracts the negatively charged electrons.

Explanation:

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3 years ago

Read 2 more answers

Suppose a yo-yo has a center shaft that has a 0.230 cm radius and that its string is being pulled.

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Answer:

Part a)

$\alpha = 782.6 rad/s^2$

Part B)

$\omega = 587 rad/s$

Part c)

$a_t = 24.3 m/s^2$

Explanation:

Part a)

As we know that

$a = R \alpha$

so we will have

$a = 1.80 m/s^2$

$R = 0.230 cm$

$\alpha = \frac{a}{R}$

$\alpha = \frac{1.80}{0.230 \times 10^{-2}}$

$\alpha = 782.6 rad/s^2$

Part B)

Angular speed of the yo-yo

$\omega = \alpha t$

so we have

$\omega = 782.6 \times 0.750$

$\omega = 587 rad/s$

Part c)

Tangential acceleration is given as

$a_t = R \alpha$

$a_t = (3.10 \times 10^{-2})(782.6)$

$a_t = 24.3 m/s^2$

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4 years ago

A train has an acceleration of magnitude 0.90 m/s2 while stopping. A pendulum with a 0.55-kg bob is attached to a ceiling of one

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The angle of the pendulum with the vertical is $5.2^{\circ}$

Explanation:

As the train decelerates, the bob of the pendulum will feel a force given by

$F=ma$

where

m = 0.55 kg is the mass of the bob

$a=0.9 m/s^2$ is the magnitude of the acceleration

In the horizontal direction.

The pendulum will be inclined at an angle $\theta$ from the vertical, so it will be in equilibrium, and therefore the horizontal component of the tension in the string must be equal to the net force F of the previous equation:

$T sin \theta = ma$ (1)

where T is the tension in the string.

We also know that the bob is in equilibrium along the vertical direction: so the vertical component of the tension must be equal to the weight of the bob,

$T cos \theta = mg$ (2)

where $g=9.8 m/s^2$ is the acceleration of gravity.

Dividing eq.(1) by eq(2), we get:

$tan \theta = \frac{a}{g}$

And therefore, we find the angle:

$\theta=tan^{-1}(\frac{a}{g})=tan^{-1}(\frac{0.90}{9.8})=5.2^{\circ}$

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3 years ago

Match the following:

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Answer:

Statement 1 can be matched with option f (Van der waal forces)

Statement 2 can be matched with option b (Liquid crystal)

statement 3 can be matched with option e (Thermal expansion)

Statement 4 can be matched with option g (Viscosity)

Statement 5 can be matched with option b (Fractional distillation)

Statement 6 can be matched with option a (Diffusion)

Statement 7 can be matched with option d (Miscible)

Explanation:

Van der waal forces are weak inter-molecular bonds found between covalent molecules e.g molecules of graphite, noble gases etc
Liquid crystals are substances that behave like liquids and its molecules orientate itself like a crystal (solid). They can be referred to as LCs.
Thermal expansion is a phenomenon where by matter changes in shape, volume and area due to a change in temperature.
Viscosity is a term used to describe a fluid's resistance to flow. It is also used to describe the internal friction that a moving liquid experiences. Oil is more viscose than liquid water
Fractional distillation is a separation technique used in separating two or more miscible liquids of close boiling points. For example petrol and diesel oil can be separated using fractional distillation. An industrial application of this technique is Fractional distillation of crude oil where crude oil is separated into its components
Diffusion is the movement of dissolved particles, gases, liquid from a region of higher concentration to a region of lower concentration until there is a equal balance. This can occur when you spray a perfume in one end of a room. You will get to smell the perfume at the other end after some time. Diffusion is fastest in gas as compared to liquids and solids.
Miscible is a word used to describe liquids forming a homogeneous mixture when dissolved in each other. Miscibility is factor to be considered when separating mixture.

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3 years ago