It's equals to zero (a=0)
We are given the following:
Bobo's swimming speed = 2.0 m/s
Width of the river = 100 m
Flowrate of the river = 6.0 m/s due east
First, we need to illustrate the problem. Draw the river with a width of 100 meters. Then, the flow of the river, east at 6 meters per second. Lastly, draw Bobo at one side of the river facing north and an arrow representing swimming speed at 2 meters per second.
Now, we can use the Pythagorean theorem to solve this rate problem.
c^2 = a^2 + b^2
c = speed of Bobo needed
a = speed of Bobo facing north
b = flow rate of the river going east
c^2 = 2^2 + 6^2
c = 6.32 m / s should be his speed to overcome the current and make a landing at the desired location.
Answer:
2.087m
Explanation:
Using the formula for calculating the maximum height reached by an object expressed as:
H = u²/2g
u is the initial speed
g is the acceleration due to gravity
Given
u = 6.4m/s
g = 9.81m/s²
Substitute into the formula:
H = 6.4²/2(9.81)
H = 40.96/19.62
H = 2.087m
Hence the height h of the highest point reached by the skateboarder on the right side of the ramp is 2.087m
Answer:
1225 J
Explanation:
The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by
where
m is the mass
g = 9.8 m/s^2 is the acceleration due to gravity
h is the height at which the object has been lifted
In this problem, we have
m = 250 kg
h = 0.5 m
So, the PE of the object is
