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Daniel [21]
3 years ago
12

Which represents the net force

Physics
1 answer:
ipn [44]3 years ago
4 0

Answer:

The net force is 500N downwards

Explanation:

When Haley is trying to pull an object upward. The below forces are acting on the object.  

Fp = 5500N

Fg = 6000N

because the force of gravity is more than the force of the pull.

Fnet = Fg - Fp = 6000N - 5500N = 500N

And, the direction of the resultant force is the direction of the larger force.

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A baseball with a mass of 0.80 kg is given an acceleration of 20.00 m/s. How much net force was applied to the ball
dybincka [34]

a x m = f

.80 x 20 = 16

4 0
3 years ago
If an object is moving with constant velocity, what do you know about its acceleration?
Ivan
It's equals to zero (a=0)
8 0
3 years ago
Bobo, the clown, can swim at 2.0 m/s. he must make a landing directly across to the north side of the styx river, which is 100.
victus00 [196]
We are given the following:

Bobo's swimming speed = 2.0 m/s
Width of the river = 100 m
Flowrate of the river = 6.0 m/s due east

First, we need to illustrate the problem. Draw the river with a width of 100 meters. Then, the flow of the river, east at 6 meters per second. Lastly, draw Bobo at one side of the river facing north and an arrow representing swimming speed at 2 meters per second.

Now, we can use the Pythagorean theorem to solve this rate problem.

c^2 = a^2 + b^2 

c = speed of Bobo needed
a = speed of Bobo facing north
b = flow rate of the river going east

c^2 = 2^2 + 6^2 

c = 6.32 m / s should be his speed to overcome the current and make a landing at the desired location. 
6 0
3 years ago
The skateboarder in the drawing starts down the left side of the ramp with an initial speed of 6.4 m/s. Neglect nonconservative
aleksandrvk [35]

Answer:

2.087m

Explanation:

Using the formula for calculating the maximum height reached by an object expressed as:

H = u²/2g

u is the initial speed

g is the acceleration due to gravity

Given

u = 6.4m/s

g = 9.81m/s²

Substitute into the formula:

H =  6.4²/2(9.81)

H = 40.96/19.62

H = 2.087m

Hence the height h of the highest point reached by the skateboarder on the right side of the ramp is 2.087m

4 0
2 years ago
A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your ans
Maksim231197 [3]

Answer:

1225 J

Explanation:

The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by

PE=mgh

where

m is the mass

g = 9.8 m/s^2 is the acceleration due to gravity

h is the height at which the object has been lifted

In this problem, we have

m = 250 kg

h = 0.5 m

So, the PE of the object is

PE=(250 kg)(9.8 m/s^2)(0.5 m)=1225 J

6 0
3 years ago
Read 2 more answers
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